Question

Rainforest data: mean = 7  σ2 = 12.405  σ ≈ 3.522 when using the formula zx = x − μ σ for the z-score for the 11.7 data point: x = ; μ =

Answer 1

Answer:

1.3344

Step-by-step explanation:

Given is the rainforest data.

Let X be the random variables

Then X has mean as 7 and variance as 12.405

SD of X = square root of variance = 3.522

We know that

$Z = \frac {X-\mu}{\sigma}\\=\frac{11.7-7}{3.522} \\=1.3344$

Z value when x = 11.7 is +1.3344

Answer 2

Answer:

Mean B =μ= 7

Standard Deviation =A=σ ≈ 3.522

Variance =σ²=12.405

X=Score=Data Point=11.7

$As, Z=\frac{X- B}{A}$

z-score for the Score 11.7

$=\frac{11.7-7}{3.522}\\\\=\frac{4.7}{3.522}\\\\Z=1.3344$