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3 years ago

9

Will mark brainliest

1 answer:

PIT_PIT [208]3 years ago

4 0

Answer:

148 deger ❤❤❤❤❤❤❤❤❤❤

32 meter

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At 4:00 AM the outside temperature was -28°F by 4:00 PM that same day it was 38° what is the sum?

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-28+28=0, and you add 38. 38 degrees.

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3 years ago

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21.evaluate 22.find dy/dx

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3 years ago

Read 2 more answers

Question 3 (1 point)

Virty [35]

Answer:

The answer to your question is (4, 6)

Step-by-step explanation:

Data

E ( 9 , 7 )

F ( - 1, 5)

Formula

$Xm = \frac{x1 + x2}{2}$

$Ym = \frac{y1 + y2}{2}$

Substitution and simplification

$Xm = \frac{9 -1}{2}$

$Xm = \frac{8}{2}$

Xm = 4

$Ym = \frac{7 + 5}{2}$

$Ym = \frac{12}{2}$

Ym = 6

Result

(4 , 6)

7 0

3 years ago