5. The way I do these problems is setting up the equation as follows:
P1V1/T1 = P2V2/T2
The units of volume and pressure can be substituted as given, since they are in relation to one another, however, the final answer must match the units provided in the question. Also, temperature must be converted to Kelvins before the equation can be used.
V1 = 50 cm^3
P1 = 825 Hg/mm
T1 = 15C = 288K
P2 = 750 Hg/mm
T2 = 47C = 320K
V2 = ?
Solve:
P1V1/T1 = P2V2/T2
(825)(50)/(288) = (750)V2/(320)
143.23 = 2.34V2
V2 = 61.21 cm^3
Answer: 6x squared+20x-56
It is hard to explain online. But I can promise you that I know what I am doing.
Answer:
$144
Step-by-step explanation:
Answer:
3 d^2 + 7 d - 7
Step-by-step explanation:
5d^2 + 4d - 3 less 2d^2 - 3d + 4
<em> correct difference</em>
3 d^2 + 7 d - 7
