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lilavasa [31]
3 years ago
14

A dance school charges a registration addition to a fee per lesson. The equation is y=30x+25 represents the total cost x lessons

. What is the cost per lesson?
Mathematics
2 answers:
Alexxandr [17]3 years ago
8 0
That would be the slope of this straight line; it's 30 units / lesson, e. g., $30/lesson.  The $25 is the registration and/or up-front cost.

Anton [14]3 years ago
7 0
The answer would be 30. You have to find the slope. You can use this formula, y=mx+b and then get the slope. $30 per lesson and the $25 is the up-front cost or the registration fee. That should help
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The sum of ages of a mother and daughter is 45 years. Five years ago, the product of their ages was four times the mother's age
icang [17]

Answer: the answer is 36

Step-by-step explanation:

we can solve this using an algebra equation

so first from the world problem, we can tell that mother and daughter's ages added together is 45 we can represent this by saying x (mother's age), plus y (daughter's age) is 45.

(x+y)=45

Then we from the problem we know that 5 years ago the product of their ages is four times the mother's age at that time. From this, we can write

(x-5)*(y-5)=4*(x-5)

Then we just subtract the common denominators which is (x-5) so then the equation becomes

(y-5)=4

add 5 to both sides

y=9

Then all we do is plug the answer for y into the very first equation

x+9=45

Subtract both sides by 9

x=36

To double-check let's put the answers in the second equation

(36-5)*(9-5)=4*(x-5)

we get

(31)*(4)=4*(31)

so it's right I think

6 0
3 years ago
MS. Winkler surveyed her students in just one class with 30 students to see how many siblings each of them had. Here are the res
makvit [3.9K]
the correct answer is b
3 0
4 years ago
Does anyone know the answer to this? i’ll mark brainliest
Ilia_Sergeevich [38]

Answer:

It is greater

Step-by-step explanation:

6 0
3 years ago
What is the resistance of a 1.00X10^2 -Ω , a 2.50-kΩ , and a 4.00-k Ω resistor connected in parallel?
Andreas93 [3]

Answer:

Therefore, the total Resistance:  R = 93.9 Ω

Step-by-step explanation:

Given

R₁ = 1 × 10²

R₂ = 2.5 kΩ = 2.5 × 10³ Ω

R₃ = 4  kΩ = 4 × 10³ Ω

Given that the given resisters are connected parallel, so using the formula to calculate the total Resistance R:

\frac{1}{R}\:=\:\frac{1}{R_1}\:+\:\frac{1}{R_2}+\frac{1}{R_3}

susbtituting R₁ = 1 × 10², R₂ = 2.5 × 10³ Ω, and R₃ = 4 × 10³ Ω

\frac{1}{R}=\frac{1}{1\times \:10^2}+\frac{1}{2.5\times \:10^3}+\frac{1}{4\times \:10^3}

Multiply by LCM of R, 100, 2500, and 4000:   20000 R

\frac{1}{R}\cdot \:20000R=\frac{1}{1\cdot \:10^2}\cdot \:20000R+\frac{1}{2.5\cdot \:10^3}\cdot \:20000R+\frac{1}{4\cdot \:10^3}\cdot \:20000R

simplify

20000=213R

Switch sides

213R=20000

Divide both sides by 213

\frac{213R}{213}=\frac{20000}{213}

Simplify

R=\frac{20000}{213}

R = 93.9 Ω

Therefore, the total Resistance:  R = 93.9 Ω

4 0
3 years ago
What is bigger 5/6 or 13/18?
san4es73 [151]
To compare fractions, you need a common denominator.
6 goes into 18 three times.  If we multiply (5/6) by 3 on top and bottom you get
\frac{15}{18}
Now we can compare numerators, since 15 > 13
\frac{5}{6} \ \textgreater \  \frac{13}{18}
4 0
4 years ago
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