Answer:
4th option
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y =
x - 6 ← is in slope- intercept form
with slope m = 
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= - 
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = -
and (a, b ) = (- 2, 5 ) , then
y - 5 = -
(x - (- 2) ) , that is
y - 5 = -
(x + 2)
Solving for <em>Angles</em>

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
Solving for <em>Edges</em>

You would use this law under <em>two</em> conditions:
- One angle and two edges defined, while trying to solve for the <em>third edge</em>
- ALL three edges defined
* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
_____________________________________________
Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:
- Two angles and one edge defined, while trying to solve for the <em>second edge</em>
- One angle and two edges defined, while trying to solve for the <em>second angle</em>
- ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]
* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.
I am delighted to assist you at any time.
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