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makvit [3.9K]
3 years ago
13

The sides of a quadrilateral ABCD move at a point speed of 2 centimeters per second. How long will it take to get around the who

le quadrilateral, if the area of the quadrilateral is 5cm2?​ PLS HELP MEEEE​
Mathematics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

that guy who's asking for money- seriously is greedy-

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Which angles appear to be congruent?<br> A 1 and 2<br> B 1 and 5<br> C 2 and 4<br> D 4 and 5
pentagon [3]

Answer:

B

Step-by-step explanation:

Those are the only ones that look similar. Hope it helps! :)

7 0
3 years ago
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You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
On a loan of $1200 at 15% annual interest, Shirley had to pay $135 interest. For how many months did she have the loan?
natulia [17]

Answer:

<u><em>9 months</em></u>

Step-by-step explanation:

Principal= P= $1200

Rate=R= 15%

Interest= I= $135

Time= T= ?

I=P*R*T/100

135= 1200*15*T/100

135*100=18000*T

13500/18000=T

T= 0.75 years

T= 0.75*12= 9 months

3 0
3 years ago
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What product does the model show?
Karolina [17]
What model? It only says please help me lol
4 0
3 years ago
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I’m still confused on how to work the percentages
Serjik [45]

Answer:

13 is your answer

Step-by-step explanation:

it's the biggest number and more students like cats

Hope this helps

God bless you

Have a great day

- Kayla :)

5 0
3 years ago
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