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Mariulka [41]
3 years ago
13

How to solve 465 subtract 238 equals what how to solve it

Mathematics
1 answer:
andrew-mc [135]3 years ago
4 0

Answer:

227 is answer

Step-by-step explanation:

       465

     - 238

       ------

then subtract

carry one from the 6

15-8 which is seven and then u better know how to do the rest

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Jacob averages 4 strikes for every 9 frames that he bowls. If he bowled 144 strikes in a season, how many frames did Jacob bowl?
katen-ka-za [31]
He had 36 frames because 4x36 is 144.
3 0
3 years ago
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Mike has three more dimes than nickels, and 5 quarters fewer than twice the number of nickels. In total, he has $3.60. How many
ExtremeBDS [4]
The answer would be 2
4 0
3 years ago
Evaluate the expression for y = -7.<br><br> 2y = __
vivado [14]

Answer:

2y=-14

Step-by-step explanation:

If y=-7 and you multiply y by 2, you do the same thing to both sides and get -7 × 2 = -14

5 0
3 years ago
Please help ME?!!!!!!
aniked [119]

Answer:

29 is your answer. I hope this helps you! Let me know if I got something wrong or if you need more help :)

Step-by-step explanation:

First, apply distributive property to 3(2+8). 3×2 and 3×8.

15 + (6 + 24) - 4^2

Add 6 and 24.

15 + 30 - 4^2

Simplify 4^2. 4^2 is the same as 4×4. 4 times 4 is 16.

15 + 30 - 16

Add 15 and 30.

45-16

Subtract.

29

29 is your answer. I hope this helps you! Let me know if I got something wrong or if you need more help :)

4 0
3 years ago
You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you
NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) =  -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0
3 years ago
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