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Natalija [7]
3 years ago
8

Help please! these questions are really confusing me

Mathematics
1 answer:
Anettt [7]3 years ago
6 0

Answer:

Figure 1: Option A :   $ \sqrt{\frac{\textbf{3}}{\textbf{2}}} $ ;   $ \frac{\textbf{1}}{\textbf{2}} $ ;  $ \sqrt{\textbf{3}}} $

Figure 2: Option B: $ \frac{\sqrt{\textbf{19}}}{\textbf{10}} $ ;     $ \frac{\textbf{9}}{\textbf{10}} $ ;  $ \frac{\sqrt{\textbf{19}}}{\textbf{9}} $

Figure 3: Option C:  $ \frac{\textbf{4}}{\textbf{5}} $  ;  $ \frac{\textbf{3}}{\textbf{5}} $ ;  $ \frac{\textbf{4}}{\textbf{3}} $

Step-by-step explanation:

$ \textbf{Sin  A} \hspace{1mm} \textbf{= } \hspace{1mm} \frac{\textbf{opp}}{\textbf{hyp}} $

$ \textbf{Cos A} \hspace{1mm} {\textbf{=} \hspace{1mm} \frac{\textbf{adj}}{\textbf{hyp}} $

$ \textbf{Tan A} \hspace{1mm} \textbf{=} \hspace{1mm} \frac{\textbf{Sin A}}{\textbf{Cos A}} $

We can simply follow these three formulas to solve the problem.

Figure 1:

Sin A = $ \frac{6\sqrt{3}}{12} $  = $ \frac{\sqrt{3}}{2} $

Cos A = $ \frac{6}{12} = \frac{1}{2} $

Tan A = $ \frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}} $  = $ \sqrt{3} $

Figure 2:

Sin A = $ \frac{2\sqrt{19}}{20} $  = $ \frac{\sqrt{19}}{10} $

Cos A = $ \frac{18}{20} = \frac{9}{10} $

Tan A = $ \frac{\frac{\sqrt{19}}{10}}{\frac{10}{9}} $ = $ \frac{\sqrt{19}}{9} $

Figure 3:

Sin A =   $ \frac{16}{20} $   = $ \frac{4}{5} $

Cos A = $ \frac{12}{20} = \frac{3}{5} $

Tan A = $ \frac{\frac{4}{5}}{\frac{3}{5}} $  = $ \frac{4}{3} $

Hence, the answer.

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