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Aliun [14]
3 years ago
6

The lengths of the legs of a right triangle are 6 cm and 8 cm. What is the length of the hypotenuse?

Mathematics
2 answers:
rosijanka [135]3 years ago
7 0
You can find the missing side of a right triangle by using the Pythagorean Theorem (a² + b² = c²), where c is the hypotenuse. So, just plug the given numbers in and solve for c.

a² + b² = c²   Plug 6 and 8 in for a and b (order doesn't matter)
6² + 8² = c²   Square both numbers
36 + 64 = c²   Add
100 = c²   Take the square root of both sides
10 = c   Switch the sides of the equation to make it easier to read
c = 10

So, the hypotenuse of the triangle is 10 cm.
Svetllana [295]3 years ago
6 0
You require the Pythagorean Theorem: in a right triangle, the sum of the squares of the legs equals the square of the hypotenuse.In this case 6^2 + 8^2 = 36 + 64 = 100 = 10^2
 the hypotenuse is 10.
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Differentiate Functions of Other Bases In Exercise, find the derivative of the function.
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Answer:

\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}

Step-by-step explanation:

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y = \log_{10}{(x^2+6x)}

using the property of log \log_ab=\frac{log_cb}{log_ca}, and if c =e,\log_ab=\frac{ln{b}}{ln{a}}, we can rewrite our function as:

y = \dfrac{\ln{\left (x^{2} + 6 x \right )}}{\ln{\left (10 \right )}}

now we can easily differentiate:

\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{d}{dx}(\ln{(x^{2} + 6x)})\right)

\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{2x+6}{x^{2} + 6x}\right)

\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}

This is our answer!

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