A
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Answer:
Nope
Step-by-step explanation:
No, it is not possible; Possible explanation: Four sides connected at these angles cannot form a closed figure. The sum of the angles in a quadrilateral is 360°. Possible quadrilaterals include a rhombus, a parallelogram, a trapezoid, and an unclassified quadrilateral.
I'm assuming you are finding the equation of the line of Line J
Slope-intercept form: y = mx + b
[m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis]
For lines to be perpendicular, the slopes have to be negative reciprocals of each other. (basically changing the sign (+/-) and flipping the fraction/switching the numerator and the denominator)
For example:
slope = 2 or 
Perpendicular line's slope =
[changed sign from + to -, and flipped the fraction]
slope = 
Perpendicular line's slope =
[changed sign from - to +, and flipped the fraction]
Since you know the slope is 3, the perpendicular line's slope is
. Plug this into the equation
y = mx + b
To find b, plug in the point (3, 8)

8 = -1 + b Add 1 on both sides to get "b" by itself
8 + 1 = -1 + 1 + b
9 = b

Answer:
Here is what the graph will look like and here are some points..