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Sergeeva-Olga [200]
3 years ago
10

A rectangle is 14 inches long and 4 inches wide. A smaller, similar rectangle is 2 inches wide. To the nearest inch, what is the

length of the smaller rectangle? A. 3 1/2 in. B. 7 in. C. 8 in. D. 18 in. Please include ALL work!
Mathematics
1 answer:
const2013 [10]3 years ago
8 0

Answer:

7 inches

Step-by-step explanation:

The ratio of width to length of the known rectangle is 4 : 14 and this simplifies to 2 : 7.

The smaller similar rectangle will have the same ratio of 2 :7.

This can also be looked at another way. The second value in the ratio is 7/2 of the first value in the ratio and the first value is 2/7 of the second value.

Example:

7/2 * 2 = 7

Example:

2/7 * 7 = 2

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Need answer ASAP <br> *MARKING BRAINLIEST
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252 in²

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The graph of a quadratic function passes through the points (-1,0), (-2,0), and (0,2). Write the quadratic function in general f
ddd [48]

Answer:

f(x)=x^2+3x+2

Step-by-step explanation:

step 1

we have the points

(-1,0), (-2,0), and (0,2)

Plot the points

using a graphing tool

see the attached figure

The graph of a quadratic function must be a vertical parabola open upward

The vertex is a minimum

The quadratic function in general form is equal to

f(x)=ax^2+bx+c

Substitute the value of x and the value of y of each given ordered pair in the general equation and solve for a,b and c

(0,2)

For x=0, y=2

substitute

2=a(0)^2+b(0)+c

c=2

(-1,0)

For x=-1, y=0

substitute

0=a(-1)^2+b(-1)+2

0=a-b+2 ----> a=b-2 ----> equation A

(-2,0)

For x=-2, y=0

substitute

0=a(-2)^2+b(-2)+2

0=4a-2b+2 ----> equation B

we have the system

a=b-2 ----> equation A

0=4a-2b+2 ----> equation B

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0=4(b-2)-2b+2

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0=4b-8-2b+2

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Find the value of a

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therefore

The quadratic function in general form is equal to

f(x)=x^2+3x+2

see the attached figure N 2 to better understand the problem

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