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3 years ago

7

Please help me somebody anybody

1 answer:

denis-greek [22]3 years ago

4 0

"two less than 3/2 of a number (x) is no more than 5 1/2"
3/2x-2</5 1/2 (</ means less than or equal to)
simplify
1.5x-2 </5.5
+2 both sides
1.5x</7.5
÷1.5 both sides
x</5
circle is closed
arrow is to the left
(1st number line )

"the sum of two times a number (x) and -2 is at least 8"
2x+-2>/8 (>/ means greater than or equal to)
2x-2>/8
+2 both sides
2x>/10
÷2 both sides
x>/5
circle is closed
arrow is to the right
(4th number line)

"seven subtracted from 4 times a number (x) is more than 13"
4x-7>13
+7 both sides
4x>20
÷4 both sides
x>5
circle is open
arrow is to the right
(2nd number line)

"four added to 3 times a number (x) is less than 19"
3x+4 <19
-4 both sides
3x <15
÷3 both sides
x <5
circle is open
arrow is to the right
(3rd number line)

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(1 point) Find two unit vectors orthogonal to a=⟨4,5,0⟩a=⟨4,5,0⟩ and b=⟨0,1,−3⟩b=⟨0,1,−3⟩ Enter your answer so that the first no

Anni [7]

Answer:

First vector

$V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}$

Second vector

$V=- \dfrac{-15i+12j+4k}{\sqrt{385}}$

Step-by-step explanation:

Given that

Vector a , a= 4 i + 5 j + 0 k

Vector b , b= 0 i + 1 j - 3 k

The orthogonal vector V is given as

V = a x b

V is the cross product of the above two vector which is orthogonal to the vectors a and b.

$V=\begin{vmatrix}i & j & k\\ 4 & 5 & 0\\ 0& 1 &-3 \end{vmatrix}\\V=i(-15-0)-j(-12-0)+k(4-0)\\V=-15i+12j+4k$

The unit vectors

$V=\pm \dfrac{-15i+12j+4k}{\sqrt{15^2+12^2+4^2}}\\\\V=+\dfrac{-15i+12j+4k}{\sqrt{385}}\\V=-\dfrac{-15i+12j+4k}{\sqrt{385}}$

First vector

$V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}$

Second vector

$V=- \dfrac{-15i+12j+4k}{\sqrt{385}}$

5 0

3 years ago

What's the difference?

Komok [63]

$\bf \begin{cases}
(-2x^2)\\
-2x^2
\end{cases}\qquad (-2x^2)-(-2x^2)\implies -2x^2+2x^2\implies ?$ you tell us

3 0

3 years ago

Is 8.3 repeating rational? If so, prove it by writing it as a fraction in the form a/b.

Allushta [10]

<span>8 1/3 (Rational) or 25/3</span>

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3 years ago

Solve each equation x+2y=1 and -x+y=2

Rudiy27

Answer:

x = -1, y = 1

Step-by-step explanation:

x + 2y = 1

Subtract 2y from both sides

x + 2y - 2y = 1 - 2y (simplify) -> x= 1 - 2y

----

-x + y = 2

Subtract y from both sides

-x + y - y + 2 - y (simplify) -> -x = 2 - y

Divide both sides by -1

$\frac{-x}{-1}$ = $\frac{2}{-1}$ - $\frac{y}{-1}$ (simplify) -> x = -2 + y

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2 years ago

How do you expressed the difference in the measures of center as a multiple of the measure of variation in a box plot when the I

pishuonlain [190]

You just use a calculator

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1 year ago