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There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
Answer:
Step-by-step explanation:
17.5% of 360 = 17.5% * 360
Let's find the derivative of that hyperbola in order to find a slope formula to help us with this equation. We already have an x and y value. The derivative is found this way:
so
. The derivative supplies us with the slope formula we need to write the equation. Sub in the x value of 3 to find what the slope is:
. So in our slope-intercept equation, x = 3, y = 1, and m = -1/3. Use these values to solve for b.
so b = 2. The equation, then, for the line tangent to that hyperbola at that given point is
Well, think about it... 90 feet times 4 bases= 360 feet.. 360 feet times 3 players= 1080 feet
