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brilliants [131]
4 years ago
5

Picture attached. help plz :)

Mathematics
2 answers:
Oksana_A [137]4 years ago
6 0
The answer is B. I need points plsss
dlinn [17]4 years ago
5 0

Answer:

B

Step-by-step explanation:

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The table shows the position of a motorcyclist after accelerating from rest. t (seconds) Plot the points in the table to create
MrRissso [65]

Instantaneous velocity represents the velocity at a particular point.

The instantaneous velocity at t = 3 is 7.7 ft/s

The table is given as:

\left[\begin{array}{cccccccc}t&0&1&2&3&4&5&6\\s&0&4.9&10.7&23.2&50.4&109.4&237.8\end{array}\right]

To calculate the instantaneous velocity at t = 0

We get the distance at t = 3

At t = 3, the distance (s) is:

s = 23.2

So, the instantaneous velocity (v) is:

v = \frac st

This gives

v = \frac{23.2}3

Divide 23.2 by 3

v = 7.7

Hence, the instantaneous velocity at t = 3 is 7.7 ft/s

See attachment for the required graph

Read more about instantaneous velocity at:

brainly.com/question/13190516

4 0
2 years ago
Jason found the measure of angle A
NNADVOKAT [17]
Jason and Allison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of 22° 8’ 6”. At the same time, Allison is standing 48 feet closer to the tree, measuring an angle of elevation of 30° 40’ 30” to the owl. If Jason and Allison are the same height, their eyes 5 feet from the ground, find the height of owl in the tree.
5 0
3 years ago
The first person to answer 1 divided by 0 gets brainlist
ivann1987 [24]

Answer:

0

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PLEASE!!! I NEED HELP WITH THIS ASAP!!!
MrRa [10]
Part 1
Total paid
=cost of the bond+commission
Total paid
32×96.7+32×10=3,414.4

Part 2
Annual interest
32×96.7
=3,094.4
3,094.4×0.08625
=266.892...Annual interest

Part 3
The effective interest rate
((1+0.08625÷12)^(12)−1)×100
=8.974%
6 0
4 years ago
(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
4 years ago
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