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marissa [1.9K]
3 years ago
12

Omplete the statement. Round to the nearest hundredth if necessary. 75.2 in. ≈≈ cm

Mathematics
1 answer:
salantis [7]3 years ago
4 0
The total is 191.008 centimeters.
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Which angles are corresponding angles?
vodomira [7]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
You buy milk that contains 180 calories per 2 cups. Use a ratio table to find the number of calories in 5.5 cups.
Ludmilka [50]

Answer:

The number of calories in 5.5 cups are <u>495</u>.

Step-by-step explanation:

Given:

You buy milk that contains 180 calories per 2 cups.

Now, to find the number of calories in 5.5 cups.

Let the number of calories in 5.5 cups be x.

As, in 2 cups there are 180 calories.

2 cups is equivalent to 180 calories.

Thus, the ratio would be 2:180.

So, in 5.5 cups there are x calories.

5.5 cups is equivalent to x calories.

Thus, the ratio would be 5.5:x.

Now, we set proportion to get the number of calories in 5.5 cups:

2:180::5.5:x

\frac{2}{180} =\frac{5.5}{x}

<em>By cross multiplying we get:</em>

2x=990

<em>Dividing both sides by 2 we get:</em>

x=495.

Therefore, the number of calories in 5.5 cups are 495.

4 0
3 years ago
In isosceles triangle GHK below, what is the value of m?
egoroff_w [7]

Answer:

the anwser is b

Step-by-step explanation:

divide 27 by 180 and you get an answer of 54

8 0
3 years ago
Read 2 more answers
1. Evaluate x2 + 10 if we let x= 3
snow_tiger [21]

Answer:

16

Step-by-step explanation:

x2 + 10 \\  = 3 \times 2 + 10 \\  = 6 + 10 \\  = 16

4 0
3 years ago
Read 2 more answers
A local board of education conducted a survey of residents in the community concerning a property tax levy on the coming local b
IrinaK [193]

Answer:

a. [ 0.454,0.51]

b. 599.472 ~ 600

Step-by-step explanation:

a)

Confidence Interval For Proportion

CI = p ± Z a/2 Sqrt(p*(1-p)/n)))

x = Mean

n = Sample Size

a = 1 - (Confidence Level/100)

Za/2 = Z-table value

CI = Confidence Interval

Mean(x)=410

Sample Size(n)=850

Sample proportion = x/n =0.482

Confidence Interval = [ 0.482 ±Z a/2 ( Sqrt ( 0.482*0.518) /850)]

= [ 0.482 - 1.645* Sqrt(0) , 0.482 + 1.65* Sqrt(0) ]

= [ 0.454,0.51]

b)

Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)

Z a/2 at 0.05 is = 1.96

Samle Proportion = 0.482

ME = 0.04

n = ( 1.96 / 0.04 )^2 * 0.482*0.518

= 599.472 ~ 600

8 0
2 years ago
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