Question

A minor league baseball team plays 128 games a seanson. If the tam won 16 more than three times as many games as they lost how many wins and losses did the team have.

Answer 1

Answer: The team won 100 games and losses 28 games

Step-by-step explanation:

Let the number of games won denoted by x and the games lost is denoted by y .

Given : A minor league baseball team plays 128 games in a season.

Team won 16 more than three times as many games as they lost.

Then, the system of equations, we have

$x+y=128-------(1)\\\\x=3y+16------------(2)$

We can rewrite equation (2) as $x-3y=16----------------(3)$

Now, Eliminate equation (3) from (1), we get

$y-(-3y)=128-16\\\\\Rightarrow\ 4y=112\\\\\Rightarrow\ y=\dfrac{112}{4}=28$

Substitute the value of y in (2), we get

$x=3(28)+16=84+16=100$

Hence, the team won 100 games and losses 28 games.