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4 years ago

Is it C or no? Can u help please

Mathematics

1 answer:

Westkost [7]4 years ago

7 0

the answer is Probably C.

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3 years ago

Here are the weights, in pounds, of a sample of 13 adult female golden retriever dogs: 59.0, 54.1, 53.7, 51.6, 57.5, 58.7, 58.0,

lidiya [134]

Answer:

95% confidence interval for the population mean weight of adult female golden retrievers is [53.01 pounds , 56.78 pounds].

Step-by-step explanation:

We are given that the weights, in pounds, of a sample of 13 adult female golden retriever dogs :

59.0, 54.1, 53.7, 51.6, 57.5, 58.7, 58.0, 53.8, 48.9, 53.9, 51.6, 55.9, and 57.4.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X }{n}$ = 54.9 pounds

s = sample standard deviation = $\frac{\sum (X-\bar X)^{2} }{n-1}$ = 3.12 pounds

n = sample of female = 13

$\mu$ = population mean weight

Here for constructing 95% confidence interval we have used One-sample t test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.179 < $t_1_2$ < 2.179) = 0.95 {As the critical value of t at 12 degree

of freedom are -2.179 & 2.179 with P = 2.5%}

P(-2.179 < $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ < 2.179) = 0.95

P( $-2.179 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X -\mu}$ < $2.179 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.179 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X +2.179 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = $\bar X \pm 2.179 \times {\frac{s}{\sqrt{n} } }$

= [ $54.9 - 2.179 \times {\frac{3.12}{\sqrt{13} } }$ , $54.9 +2.179 \times {\frac{3.12}{\sqrt{13} } }$ ]

= [53.01 pounds , 56.78 pounds]

Therefore, 95% confidence interval for the population mean weight of adult female golden retrievers is [53.01 pounds , 56.78 pounds].

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4 years ago