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3 years ago

Find the distance from the origin to the graph of 7x + 9y + 11 = 0

Mathematics

1 answer:

seraphim [82]3 years ago

7 0

Answer:

the distancev from 7±9y±11=0 is 0.97

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Josie selected a number n. She divided n by 2 and then subtracted 0.5 from the result. She took half of that result and then sub

ycow [4]

Your answer is N= Forty three

8 0

3 years ago

Read 2 more answers

Which is the completely factored form of 12x3 – 60x2 4x – 20? 4(3x2 – 1)(x – 5) 4x(3x2 1)(x – 5) 4x(3x2 – 1)(x 5) 4(3x2 1)(x – 5

Neporo4naja [7]

The factors of the polynomial are $\rm 4(3x^2 + 1)(x-5)$ .

<h3>Factorization;</h3>

Factorization is nothing but writing a number as the product of smaller numbers.

Given

Polynomial; $\rm 12x^3 - 60x^2 + 4x -20$

To find the factorization the polynomial equates the equation with zero following all the steps given below.

Then,

The factor of the polynomial is;

$\rm 12x^3 - 60x^2 + 4x -20\\\\ 12x^3(x-5)+4(x-5)\\\\(12x^3+4)(x-5)\\\\ 4(3x^2 + 1)(x-5)$

Hence, the factors of the polynomial are $\rm 4(3x^2 + 1)(x-5)$ .

To know more about factorization click the link given below.

brainly.com/question/17595467

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2 years ago

A city hosted a music festival that included three concerts. According to the sales database, 28% of the audience attended the f

Vitek1552 [10]

Answer:

$P(X\cap Y\cap Z)=0.05$

Step-by-step explanation:

From the question we are told that:

Percentage of audience in first concert $P(X)=0.28$

Percentage of audience in second concert $P(Y)=0.42$

Percentage of audience in third concert $P(Z)=0.30$

Audience Percentage at at-least one concert $P(X \cup Y \cup Z)=0.80$

Percentage of audience at first & second concert $P(X \cap Y)=0.10$

Percentage of audience in first & third concert $P(X \cap Z)=0.08$

Percentage of audience in second & third concert $P(Y\cap Z)=0.07$

Generally the equation for probability of attending all concerts $P(X\cap Y\cap Z)$ is mathematically given by

$P(X \cup Y \cup Z)=P(X)+P(Y)+P(Z)-P(X \cap Y)-P(X \cap Z)-P(Y\cap Z)+P(X\cap Y\cap Z)$

$P(X\cap Y\cap Z)=P(X \cup Y \cup Z)-P(X)-P(Y)-P(Z)+P(X \cap Y)+P(X \cap Z)+P(Y\cap Z)$

$P(X\cap Y\cap Z)=0.80-0.28-0.42-0.30+0.10+0.80+0.70$

$P(X\cap Y\cap Z)=0.05$

Therefore the probability that a randomly selected audient attended all the concerts

$P(X\cap Y\cap Z)=0.05$

8 0

3 years ago

Sales tax in the state is 7.75.write the number used to figure the sales tax on a purchase

alexira [117]

7.75÷100=0.775

Answer: 0.775

7 0

3 years ago

F/2-22<48, I want to know what f equals. Worth 30 points.

yarga [219]

$\frac{F}{2} -22\ \textless \ 48 \\ \frac{F}{2} \ \textless \ 48+22 \\ \frac{F}{2} \ \textless \ 70\ \ \ \ \ \ \ \ \ |*2 \\ F\ \textless \ 140 \\ \\ \boxed {F\in(-\infty\ ;\ 140)} \\ \\ \\ \\ \\ \\ \underline {\underline{Regards\ M.Y.}}$

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3 years ago