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zlopas [31]
3 years ago
15

In a four year period, about 80,000 acres of coastal wetlands in the United States are lost each year. What integer represents t

he total change in coastal wetlands? Write an equation and solve. (Hint: They are being lost.)
Mathematics
1 answer:
klemol [59]3 years ago
7 0

Answer:

-320000

Step-by-step explanation:

Given

Lost Land = 80,000 acres yearly

Duration 4 years

Required

The total change

Represent the total change with y;

y is calculated as thus;

y = Lost\ Land * Duration

y = -80,000 acres * 4

y = -320000\ acres

<em>Hence, a total of 320000 acres were lost during the period</em>

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andrew11 [14]

Answer:

D. y=-1/5(x)

Step-by-step explanation:

To find the equation of a line, use the formula y=mx+b, where x and y represent your x and y coordinates, m is your slope and b is your y-intercept.

b is you y-intercept, this is where the line cuts the y-axis. We can see from the graph that the line cuts the y-axis at (0,0), so c=0.

Now we have y=mx

Sub in one of our points (10,-2):

-2=m10

m=-1/5

So our equation looks like this:

y=-1/5(x)

3 0
3 years ago
Help me please &lt;3<br><br> place &lt;,&gt;, or = in the blank <br> 17/2 ________√70
Georgia [21]

Answer:

>

Step-by-step explanation:

17/5 is 8.5 but √70 is 8.3 something that for 17/2>√70

7 0
4 years ago
Suppose the parent population has an exponential distribution with a mean of 15 and standard deviation of 12. Use the Central Li
bazaltina [42]

Answer:

The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the population, we have that:

Mean = 15

Standard deviaiton = 12

Sample of 30

By the Central Limit Theorem

Mean 15

Standard deviation s = \frac{12}{\sqrt{30}} = 2.19

Approximately normal

The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.

4 0
3 years ago
If jim had 8 apples and you took 5 away and gave him two back how many apples do you have?
max2010maxim [7]
5 apples is the correct answer:)
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3 years ago
Which relation is a function
faltersainse [42]

Answer:

The relation on the bottom left, where the mouse is, is the function. Hope this helps :)

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3 years ago
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