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alexgriva [62]
3 years ago
8

Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots. If this player shoots twi

ce, the exact probability that he scores a goal both times is
Mathematics
2 answers:
Kipish [7]3 years ago
7 0

Answer:

<em>The probability of scoring two goals in both times is</em><em> 0.137 or 13.7%</em>

Step-by-step explanation:

Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots.

So P(A)=0.63

Hence, the probability of getting success in his shoots will be,

P(A^c)=1-P(A)=1-0.63=0.37

The probability of scoring two goals in both times is,

=P(A^c)\cdot P(A^c)

=0.37\times 0.37

=0.137

=13.7\%

saveliy_v [14]3 years ago
6 0
If he misses 63%, then he makes it 37% each time he shoots.
To calculate the probability if he makes it both times, you multiply it together:
37% * 37% = 13.69%

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