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2 years ago

11

Jeez math help please!!!!!

1 answer:

viva [34]2 years ago

4 0

(3y^7)^3 3^3*y^(7*3)
------------ = ------------------
9y^9 9*y^9

(3y^7)^3 3^3*y^(7*3) 27*y^21 (mult. together the exponents 3 and 7)
------------ = ------------------ = --------------
9y^9 9*y^9 9*y^9

That 27/9 reduces to 3. y^(21) / y^9 reduces to y^12.

Thus, we obtain 3*y^12 (answer)

Please do the next one, asking questions if need be, and showing your work.

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