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Zepler [3.9K]
3 years ago
11

Jeez math help please!!!!!

Mathematics
1 answer:
viva [34]3 years ago
4 0
(3y^7)^3      3^3*y^(7*3)              
------------ = ------------------   
    9y^9           9*y^9

(3y^7)^3      3^3*y^(7*3)        27*y^21      (mult. together the exponents 3 and 7)
------------ = ------------------ = --------------
    9y^9           9*y^9                 9*y^9

That 27/9 reduces to 3.     y^(21) / y^9  reduces to y^12.

Thus, we obtain           3*y^12   (answer)

Please do the next one, asking questions if need be, and showing your work.

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What’s 1+1 I am so confused I am in middle school and this is the hardest question 10 points if u get it right lol
julsineya [31]

Answer:

It depends how you were taught. You could say it's 11 (eleven) or 2.

6 0
3 years ago
Read 2 more answers
A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther
mariarad [96]
<h2>Answer:</h2>

<em><u>Recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\

Therefore, on checking, we observe that,

a_{n}=a_{n-1}+(n-1)^{2}

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

<u>At, </u>

<u>n = 1</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0

which is true.

<u>At, </u>

<u>n = 2</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1

Which is also true.

<u>At, </u>

<u>n = 3</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5

Which is true.

<u>At, </u>

<u>n = 4</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14

This is also true at the given value of 'n'.

<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

3 0
3 years ago
Solve the equation. If there is no solution, write no solution. –2 |h – 7| = –28
Elodia [21]
The answer is, A) No solution
8 0
3 years ago
As part of a science experiment, Sam recorded the four values shown in the table, but one of them got smudged on his paper. He r
denpristay [2]

Answer:

D) 4

Step-by-step explanation:

−9 + 12 + (unknown) + −8 = −1

<em>Start by going through and testing each option</em>

−9 + 12 + 2 + −8 =

3 + 2 + −8 =

5 + −8 =

−3

−3 ≠ −1

<em>A) 2 is not possible.</em>

−9 + 12 + −2 + −8 =

3 + −2 + −8 =

1 + −8 =

−7

−7 ≠ −1

<em>B) </em>−<em>2 is not possible.</em>

−9 + 12 + −4 + −8 =

3 + −4 + −8 =

−1 + −8 =

−9

−9 ≠ −1

<em>C) </em>−4<em> is not possible.</em>

<em>From this, D is looking like the answer. But to be sure, test it.</em>

−9 + 12 + 4 + −8 =

3 + 4 + −8 =

7 + −8 =

−1

−1 = −1

<em>D) 4 is the answer.</em>

5 0
3 years ago
How do you solve quadratic equations?
masha68 [24]
In any equation there is a variable (usually x). In a quadratic equation there is a lot involved.

-B (+or-) sqrt of b^2 - 4 x A x C
________________________  divide it by
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                                                   There is usually an original equation that looks like:  Ax^2 + Bx + C = 0    Use the variables from the equation to the left to fill the upper equation.  (You can also look up a better formula if confused).

8 0
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