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3 years ago

Jeez math help please!!!!!

Mathematics

1 answer:

viva [34]3 years ago

4 0

(3y^7)^3 3^3*y^(7*3)
------------ = ------------------
9y^9 9*y^9

(3y^7)^3 3^3*y^(7*3) 27*y^21 (mult. together the exponents 3 and 7)
------------ = ------------------ = --------------
9y^9 9*y^9 9*y^9

That 27/9 reduces to 3. y^(21) / y^9 reduces to y^12.

Thus, we obtain 3*y^12 (answer)

Please do the next one, asking questions if need be, and showing your work.

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What’s 1+1 I am so confused I am in middle school and this is the hardest question 10 points if u get it right lol

julsineya [31]

Answer:

It depends how you were taught. You could say it's 11 (eleven) or 2.

6 0

3 years ago

Read 2 more answers

A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

3 years ago

Solve the equation. If there is no solution, write no solution. –2 |h – 7| = –28

Elodia [21]

The answer is, A) No solution

8 0

3 years ago

As part of a science experiment, Sam recorded the four values shown in the table, but one of them got smudged on his paper. He r

denpristay [2]

Answer:

D) 4

Step-by-step explanation:

−9 + 12 + (unknown) + −8 = −1

Start by going through and testing each option

−9 + 12 + 2 + −8 =

3 + 2 + −8 =

5 + −8 =

−3

−3 ≠ −1

A) 2 is not possible.

−9 + 12 + −2 + −8 =

3 + −2 + −8 =

1 + −8 =

−7

−7 ≠ −1

B) −2 is not possible.

−9 + 12 + −4 + −8 =

3 + −4 + −8 =

−1 + −8 =

−9

−9 ≠ −1

C) −4 is not possible.

From this, D is looking like the answer. But to be sure, test it.

−9 + 12 + 4 + −8 =

3 + 4 + −8 =

7 + −8 =

−1

−1 = −1

D) 4 is the answer.

5 0

3 years ago

How do you solve quadratic equations?

masha68 [24]

In any equation there is a variable (usually x). In a quadratic equation there is a lot involved.

-B (+or-) sqrt of b^2 - 4 x A x C
________________________ divide it by
2 x A
There is usually an original equation that looks like: Ax^2 + Bx + C = 0 Use the variables from the equation to the left to fill the upper equation. (You can also look up a better formula if confused).

8 0

3 years ago