Question

Jeez math help please!!!!!

Answer 1

(3y^7)^3      3^3*y^(7*3)              
------------ = ------------------   
    9y^9           9*y^9

(3y^7)^3      3^3*y^(7*3)        27*y^21      (mult. together the exponents 3 and 7)
------------ = ------------------ = --------------
    9y^9           9*y^9                 9*y^9

That 27/9 reduces to 3.     y^(21) / y^9  reduces to y^12.

Thus, we obtain           3*y^12   (answer)

Please do the next one, asking questions if need be, and showing your work.