You can solve them by using the law of cos, then the law of sin First: use the law of the cos to find the side that corresponds to the angle given: for example, #10 (the unknown side)^2= (a given side)^2+(the other given side)^2-2(a given side)(the other given side)(Cos(the degree of the corresponding angle of the unknown side) Official formula: c^2=a^2+b^2-2abCosC d=((3)^2+(4)^2-2(3)(4)Cos(30degree))^1/2 d=(9+16-24((3)^1/2)/2)^1/2(simplify) d=2.053(to the 3rd decimal place, as reference)
Secondly, use the law of sin to find out the remaining sides Sin(One angle)/corresponding side=Sin(another angle)/corresponding side=Sin(the third angle)/corresponding side, officially: Sin(A)/a=Sin(B)/b=Sin(C)/c in this case: Sin(30degree)/2.053=SinB/3(find the non obtuse angle using the law of sin, because it can not deal with an obtuse angle) 3xSin(30)/2.053=SinB Sin^-1(3xSin(30degree)/2.053)=B 71.766=A=B 46.94(degree)=B
Thirdly, fin the third, larger angle by subtraction 46.94+30+C=180 C=180-46.94-30 C=103.06
First, you subtract the base fee of $3.50, which gives you $18.00. Then you subtract as many sevens there are in 18, which is two. And then your answer is shown, as two. Hope this helps!
