Answer:
I can’t give you the answer but there this google app
Step-by-step explanation:
Called algebratiger
69. Oh yes the memes indeed.
Answer:
90 mph
Step-by-step explanation:
Against wind DATA:
distance = 600 miles ; time = 5 hrs. ; rate = 600/5 = 120 mph
With wind DATA:
distance = 600 miles ; time = 2 hrs ; rate = 600/2 = 300 mph
Equations:
p + w = 300
p - w = 120
2p = 420
p = 210 mph (speed of the plane in still air)
Since p+w = 300, w = 300-210 = 90 mph (speed of the wind)
Answer:
cos(θ) = 3/5
Step-by-step explanation:
We can think of this situation as a triangle rectangle (you can see it in the image below).
Here, we have a triangle rectangle with an angle θ, such that the adjacent cathetus to θ is 3 units long, and the cathetus opposite to θ is 4 units long.
Here we want to find cos(θ).
You should remember:
cos(θ) = (adjacent cathetus)/(hypotenuse)
We already know that the adjacent cathetus is equal to 3.
And for the hypotenuse, we can use the Pythagorean's theorem, which says that the sum of the squares of the cathetus is equal to the square of the hypotenuse, this is:
3^2 + 4^2 = H^2
We can solve this for H, to get:
H = √( 3^2 + 4^2) = √(9 + 16) = √25 = 5
The hypotenuse is 5 units long.
Then we have:
cos(θ) = (adjacent cathetus)/(hypotenuse)
cos(θ) = 3/5