Write a multiplication equation that shows the denominator of 3/4 and 1/2 are related

1 answer:

6 0

Hope that “3/4 x 2/4” is what you are looking for. You have to multiply the numerator and the denominator of the second term by 2.

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Pls help with Question 11.<br> I need to submit it by tmr

Wewaii [24]

Answer: 81.85 km/hr

Converting m/sec into km/hr, 25 m/sec = 90 km/hr

Average =

Time = 50/90 = 5/9 hr

next 120 km at an average speed of 80km/h

=> Time = 120/80 = 3/2 hr

last part of its journey at an average speed of 90km/h in 35 Minutes

time = 35 minutes = 35/60 hr = 7/12 hr

Distance covered = 90 * 7 /12 = 105/2 km

Total Distance = 50 + 120 + 105/2 = 435/2 km

Total time = 5/9 + 3/2 + 7/12 = ( 20 + 54 + 21) /36 = 95/36

Average speed = (435/2)/(95 /36) = 432 * 18 /95 = 81.85 km/hr

8 0

3 years ago

Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .

Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of $F$ around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

$F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle$

Therefore,

$P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y$

Let's calculate the needed partial derivatives.

$P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0$

Thus,

$Q_x -P_y = 0 -2 = - 2$

Now, by the Green's theorem, we have

$\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x \Big|_{-3}^{4} = -42$