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schepotkina [342]
3 years ago
9

Henry bought pound of roasted almonds for $5. He wants to know the price per pound. What is the price per pound?

Mathematics
2 answers:
butalik [34]3 years ago
3 0

Answer:

5$

Step-by-step explanation:

he bought a pound for 5

Sophie [7]3 years ago
3 0

Answer:

6!

Step-by-step explanation:

(I did the quiz)

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Janelle earns $950 a week.Carter earns $50,320 a year.Each works 52 weeks a year.What is the difference between the amounts Jane
Dvinal [7]
First, let's figure out how much money Carter earns in 1 year.  This is equal to 50,320*30 = 1,509,600, so Carter makes $1,509,600 in 30 years.

Next, we need to figure out how much money Janelle makes.  We can do this two ways.  We can figure out how many weeks are in 30 years, or we can figure out how much money Janelle makes in a year and then multiplying that name by 30.  I will solve this problem in the second way.

In order to figure out how much money Janelle makes in a year, we do 950*52 = 49,400.  Janelle makes 49,400 per year.  Now, we multiply this number by 30 to see how much she makes in 30 years.  49,400*30 = 1,482,000.  Janelle makes $1,482,000 in 30 years.

Now, we need to finish the problem.  We do this by subtracting the amount of money that Janelle makes from the amount of money that Carter makes.  This is: 1,509,600 - 1,482,000 = 27,600.  The difference between the amount that Janelle makes and Carter makes in 30 years is $27,600
6 0
3 years ago
The student council needs 2/3 of its members to vote favorably for a motion in order for it to pass. currently, 2/7 of the membe
AfilCa [17]

Answer:

8/21

Step-by-step explanation:

First, we need to have like denominators.

3*7=21

2/3= 14/21

2/7= 6/21

14-6=8

Answer: 8/21

3 0
3 years ago
You are having notices professionally printed. Design cost are $19.00. The first hundred notices cost $5.50 and additional notic
victus00 [196]
$50 - $19 = $31
$31 - $5.50 = $25.50
$4.95 ÷ $25.50 = 5
5 x 100 = 500 notices
7 0
3 years ago
Please help I will brainliest!! Really urgent!!
Sergeeva-Olga [200]

Answer:

11x + 5

Step-by-step explanation:

Hope this helps!!!

7 0
3 years ago
Read 2 more answers
The mean number of words per minute (WPM) read by sixth graders is 97 with a standard deviation of 19 WPM. If 75 sixth graders a
andrey2020 [161]

Answer:

0.0174 = 1.74% probability that the sample mean would be greater than 101.63 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}};

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 97, \sigma = 19, n = 75, s = \frac{19}{\sqrt{75}} = 2.1939

What is the probability that the sample mean would be greater than 101.63 WPM?

This is 1 subtracted by the pvalue of Z when X = 101.63. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{101.63 - 97}{2.1939}

Z = 2.11

Z = 2.11 has a pvalue of 0.9826.

1 - 0.9826 = 0.0174

0.0174 = 1.74% probability that the sample mean would be greater than 101.63 WPM

5 0
3 years ago
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