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Vesna [10]
3 years ago
14

M is the midpoint of LN. what is LM?

Mathematics
2 answers:
Serjik [45]3 years ago
7 0
Given, 

M is the midpoint of LN.

Thus,

LM = MN

3x = 2x + 2

3x - 2x = 2

x = 2

Hence,

LM = 3x = 3 * 2 = 6

Hence, LM is 6 units.
kherson [118]3 years ago
4 0

Answer:  LM = 6 units.

Step-by-step explanation: Given that the point M is the mid-point of the line segment LN shown in the figure.

We are to find the length of LM.

From the figure, we note that

LM = 3x  and  MN = 2x + 2.

Since M is the mid-point of LN, so it will divide LN in two equal parts.

That is, we must have

LM=MN\\\\\Rightarrow 3x=2x+2\\\\\Rightarrow 3x-2x=2\\\\\Rightarrow x=2.

Therefore, we get

LM=3\times2=6~\textup{units}.

Thus, LM = 6 units.

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Answer:

58.5 ft²

Step-by-step explanation:

The figure is made up of a square, triangle and rectangle. Thus, the area of the figure is the sum of the areas of the square, triangle and rectangle.

Let's find the area of each!

<u>Square</u>

Area of square= side ×side

Area

= 3(3)

= 9 ft²

<u>Triangle</u>

Area of triangle= ½ ×base ×height

Base= 11 ft

Height= 3 ft

Area

= ½(11)(3)

= 16.5 ft²

<u>Rectangle</u>

Area of rectangle= length ×breadth

Area

= 3(11)

= 33 ft²

Area of figure

= 9 +16.5 +33

= \textcolor{red}{58.5 \: {\text{ft}} {}^{2} }

8 0
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Answer:

$35,537.51

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=7%20%5Cfrac%7B2%7D%7B3%7D%20%20" id="TexFormula1" title="7 \frac{2}{3} " alt="7 \frac{2}{3}
sammy [17]

Answer:

7 \frac{2}{3}=\frac{7*3+2}{3}=\frac{23}{3}

7 \: \frac{1}{2}=\frac{7*2+1}{2}=\frac{15}{2}

5842 \div 23=254

8 0
3 years ago
My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the
AVprozaik [17]

Answer:

a) n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

b) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.9=0.1 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

8 0
3 years ago
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