What's it asking you only have half of the promblem
Circumference = πd = 3.14*559 = 1755.26
The spokes divide the circumference into 32 arcs. Each arc length is 1755.26/32 = 54.75 mm
Answer:
a^5b^4
-a^5b^4
9a^5b^4
Step-by-step explanation:
Like terms will all have the same bases and exponents.
a^5b^4
-a^5b^4
9a^5b^4
they all contain a^5 b^4
Answer:6018
Step-by-step explanation:
Given Sequence

It represent an A.P. with
first term 
common difference 
So sum of 51 term
![S_n=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
![S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B2%5Ctimes%20%28-282%29%2B%2851-1%2916%5D)
![S_{51}=\frac{51}{2}\times [-564+800]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B-564%2B800%5D)
![S_{51}=\frac{51}{2}\times [236]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B236%5D)


Just dividing the volumes of the pan, 189 and one bar, 3, suggests that at most she'll be able to cut 63 bars.
But you'll also have to prove that you can divide it in a regular pattern. And you can:
9 divides by 1
10.5 divides by 1.5
2 divides by 2.
So no incomplete bars!