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morpeh [17]
3 years ago
15

Find the volume of the cylinder. Use 3.14 for a.

Mathematics
1 answer:
vitfil [10]3 years ago
5 0
24501.42m3 is the answers
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HElp fasttttttttttttttttttttttttt
Eduardwww [97]

9514 1404 393

Answer:

  -0.16

Step-by-step explanation:

The 'a' value can be found by looking at the difference between the y-value of a point 1 unit from the vertex, and the y-value of the vertex.

Here, that is a negative fraction of a unit. If we assume the value is a rational number that can be accurately determined from this graph, then we can find it by looking for a point where the graph crosses a grid intersection. It looks like such grid points are (-7, 0) and (3, 0). The vertex is apparently (-2, 4), so the vertex form of the equation is ...

  y = a(x +2)^2 +4

Using the point (3, 0), we have ...

  0 = a(3 +2)^2 +4 . . . . . fill in the values of x and y

  -4 = 25a . . . . . . . . . . subtract 4; next, divide by 25

  a = -4/25 = -0.16

7 0
3 years ago
What is the midpoint m given q(-2, -4) and R(6, 10)
xxMikexx [17]

Answer:

(2,3)

Step-by-step explanation:

8 0
3 years ago
I'm don't understand polygons, as you should know
lawyer [7]

Answer:

540°

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

Here n = 5, thus

sum = 180° × 3 = 540°

8 0
3 years ago
Read 2 more answers
If the endpoints of ST are S (1,4) and T (5,2) then the midpoint is in Quadrant IV?
irina [24]

It is false that the midpoint is in quadrant IV

<h3>How to determine the midpoint location?</h3>

The endpoints are given as:

S (1,4) and T (5,2

The midpoint is

(x, y) = 0.5 *(x1 + x2, y1 + y2)

So, we have:

(x, y) = 0.5 *(1 + 5, 4 + 2)

Evaluate the expression

(x, y) = (3, 3)

The point (3, 3) is located in the first quadrant

Hence, it is false that the midpoint is in quadrant IV

Read more about quadrants at:

brainly.com/question/7196312

#SPJ1

6 0
2 years ago
Whats the Axis of Symmetry? willing to give 15 points !!
nydimaria [60]

The axis of symmetry of a parabola in the form

y=ax^2+bx+c

is a vertical line

x=k

where k is the x coordinate of the vertex of the parabola.

The x coordinate of the vertex of the parabola is given by

-\dfrac{b}{2a}

which in your case is

-\dfrac{-6}{2\cdot \frac{1}{4}}=\dfrac{6}{\frac{1}{2}}=6\cdot 2=12

So, the axis of symmetry is the line x=12.

4 0
3 years ago
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