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Alchen [17]
3 years ago
10

A taxi fare has a fixed charge of 1.75 and an additional charge 0.45 per mile. A fare for m miles is 13.90. Which equation could

be used to find m miles? A. 1.75(13.90+m) = 1 B. 1.75+0.45m = 13.90 C. 0 45 +1.75m =13.90 D. (0.45 + 11.20)m = 1.75
Mathematics
1 answer:
Pavel [41]3 years ago
3 0

Answer:

The answer is 27 miles and option b will give that.

Step-by-step explanation:

1.75 + 0.45m = 13.90

m = (13.90 - 1.75) / 0.45

m = 27 miles

Hope this helped

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1. Kim's age is twice that of her sister. When you add Kim's age to her sister's age, you get 36. How old is each sister? (a) Wr
Jlenok [28]
A)
Kim's age=k
Sister's age=s
k=2s
k+s=36
b)
k=2s
k+s=36
k=36-s
2s=36-s
3s=36
s=12
12*2=24
Kim is 24 and her sister is 12

Hope this helps :)

6 0
3 years ago
Read 2 more answers
Help me please ASAP
brilliants [131]

ans is c it is simple c only meet the need of questions

4 0
3 years ago
Please help me with this problem <br> Evaluate (-½·3)³
-Dominant- [34]

Answer: -27/8

Step-by-step explanation:

\left(-\frac{1}{2}\cdot \:3\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\quad \mathrm{if\:}n\mathrm{\:is\:odd}

\left(-\frac{1}{2}\cdot \:3\right)^3=-\left(\frac{1}{2}\cdot \:3\right)^3

=-\left(\frac{1}{2}\cdot \:3\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

\left(\frac{1}{2}\cdot \:3\right)^3=\left(\frac{1}{2}\right)^3\cdot \:3^3

=-\left(\frac{1}{2}\right)^3\cdot \:3^3

=-\frac{1}{8}\cdot \:3^3

=-\frac{1}{8}\cdot \:27

=-\frac{27}{8}

3 0
2 years ago
First 8 is added to me , then j am multiplied by 6.then 40 is subtracted from me .Finally I am divided by 10. The result is 11.
alexdok [17]
11x10=110
110+40=150
150/6=25
25-8=17
17 is the number.
4 0
3 years ago
Find the complete factorization of the expression. 12xy + 28xz A) 4yz(10x) B) 4yz(3x + 7x) C) 4x(3y + 7z) D) 4(3xy + 7yz)
VashaNatasha [74]

Answer:

<em>The correct option is:  C)  4x(3y + 7z)</em>

Step-by-step explanation:

Given expression is:   12xy+28xz

First we need to find the GCF(Greatest common factor) of 12xy and 28xz and then we will factor out that GCF.

12xy \Rightarrow 2\times 2\times 3\times x\times y\\ \\ 28xz\Rightarrow 2\times 2\times 7\times x\times z

We can see that the common factors are:  2,2, x

So, the GCF will be:  2\times 2\times x= 4x

Now factoring out 4x from the given expression, we will get.....

12xy+28xz\\ \\ = 4x(\frac{12xy}{4x}+ \frac{28xz}{4x}) \\ \\ =4x(3y+7z)

So, the complete factorization will be:  4x(3y+7z)

7 0
3 years ago
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