Question

Write an equation of a line that passes through the given point and has slope m (3,4) m=1/2

Answer 1

Y - y₁ = m(x - x₁)
y - 4 = ¹/₂(x - 3)
y - 4 = ¹/₂x - 1¹/₂
  + 4           + 4   
     y = ¹/₂x + 5¹/₂

Answer 2

Plug the point and the slope into point-slope form and simplify to get it in slope-intercept form.

$\sf~y-y_1=m(x-x_1)$

Where y1 is the y-value of the point, x1 is the x-value, and 'm' is the slope.

$\sf~y-4=\dfrac{1}{2}(x-3)$

Distribute 1/2:

$\sf~y-4=\dfrac{1}{2}x-1.5$

Add 4 to both sides:

$\boxed{\sf~y=\dfrac{1}{2}x+2.5}$

or

$\boxed{\sf~y=\dfrac{1}{2}x+2\dfrac{1}{2}}$