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3 years ago

What is 10 time 10 ?

Mathematics

2 answers:

Ray Of Light [21]3 years ago

4 0

Answer:

100

Step-by-step explanation:

10 * 10 = 100

* 10

100

multiply the zeros 0 * 0 = 0

multiply the zero by the one 0 * 1 = 0

do that again 0 * 1 = 0

multiply one by one 1 * 1 = 1

you have the 1 in the hundreds place, add the 2 zeros to the end

100

lol i hope this helps! :)

ycow [4]3 years ago

3 0

Answer:

100

Step-by-step explanation:

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FrozenT [24]

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3 years ago

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6.2×0.03= and tell me how you did it please

matrenka [14]

Answer:

0.186

Step-by-step explanation:

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8 0

3 years ago

The amount of trout y (in tons) caught in a lake from 1995 to 2014 can be modeled by the equation y = -0.08x2 + 1.6x + 10, where

Lapatulllka [165]

For this case, the first thing we want to do is substitute the value of y = 15 in the equation.
We have then:
15 = -0.08x ^ 2 + 1.6x + 10
Rewriting we have:
0 = -0.08x ^ 2 + 1.6x + 10 - 15
0 = -0.08x ^ 2 + 1.6x - 5
The solutions are:
x1 = 3.876275643042054
x2 = 16.123724356957947
Nearest whole number:
x1 = 4
x2 = 16
were about 15 tons of trout caught in the lake in the years:
1995 + 4 = 1999
1995 + 16 = 2011
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The year 1999 and the year 2011

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3 years ago

Carol bought 12 pounds of bananas for $13.50 and then the next week she bought 20 pounds for $22. Which bunch of bananas was the

DENIUS [597]

The answer is B) 20 lbs for $22 because carol is getting 8 pounds more for only $9+

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3 years ago

Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we

Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N( $\mu = 7 lbs , \sigma^{2} = 0.875^{2} lbs$ )

The standard normal z distribution is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean weight

n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{7.5-7}{\frac{0.875}{\sqrt{4} } }$ ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0

3 years ago