P(B) = 8/12
P(R | B) = 4/11
P(B ∩ R) = 8/33
The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent
<em><u>Solution:</u></em>
<em><u>The probability is given as:</u></em>
Given that,
A box contains four red balls and eight black balls
Red = 4
Black = 8
Total number of possible outcomes = 12
Let event B be choosing a black ball first and event R be choosing a red ball second.
<h3><u>Find P(B)</u></h3><em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>
Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent