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ycow [4]
3 years ago
13

Express 0.003597 to three significant figures​

Mathematics
1 answer:
coldgirl [10]3 years ago
3 0

Answer:

0.00360.

Step-by-step explanation:

Leading zeros in a number are not significant, so your number has four significant figures.

You must drop the 7 from 0.003597.

Since 7 is greater than 5, you must add 1 to the 9

\begin{array}{r|l}1&  \\0.00359 &\text{7}\!\!\!\!\diagup \\\mathbf{0.00360} & \\\end{array}

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Ms. Mor ris has 35 tests to grade this weekend. Mrs. Cook has 80% more tests than that to grade this weekend. How many tests doe
Serga [27]

Answer:

Mrs. Cook has to grade 63 tests.

Step-by-step explanation:

In order to find the answer, first you have to calculate 80% of the number of tests Ms. Morris has:

35*80%= 28

Then, you have to add the number that represents 80% to the number of tests Ms. Morris has to grade:

35+28=63

According to this, the answer is that Mrs. Cook has to grade 63 tests.

8 0
3 years ago
Help me please I’m behind
BaLLatris [955]

Answer:

1. D 2.A 3.D 4.D

Step-by-step explanation:

6 0
3 years ago
45 Points! <br> Please help with this it's either B or C
Nadya [2.5K]
It's C I'm pretty sure and this in English not math
4 0
3 years ago
Read 2 more answers
Plz write this on paper help me and send it❤️
vovangra [49]

Answer:

1. 27^{\frac{2}{3} } =9

2. \sqrt{36^{3} } =216

3. (-243)^{\frac{3}{5} } =-27

4. 40^{\frac{2}{3}}=4\sqrt[3]{25} =4325

5. Step 4: (\frac{343}{27}) ^{-1} =\frac{27}{343}

6. D. -72cd^{7}

Step-by-step explanation:

Use the following properties:

a^{\frac{x}{y} } =\sqrt[x]{a^{y} }

\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}

a^{-n} =\frac{1}{a^{n} }

(xy)^{z} =x^{z} y^{z} \\\\

(x^{y}) ^{z} =x^{yz}

x^{y} x^{z} =x^{y+z}

So:

1. 27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9

2. \sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36}  \sqrt{36} =6*6*6=216

3. (-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27

4. 40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325

5. (\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}

6.

(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}

7 0
3 years ago
Given:<br>AC – AR<br>&lt;1 = &lt;2<br>Prove:<br>&lt;3 =&lt;4<br><br>​
Katena32 [7]

Answer:

ΔCTA ≅ ΔDRA

Step-by-step explanation:

Triangles CTA and DRA are congruent by ASA postulate. This is because:

  • ∠1 ≅ ∠2 (given)
  • AC ≅ AR (given)
  • ∠A is the same for both triangles (they are opposite angles)

Then, correspondent angles and sides are congruent, for example, ∠3 ≅ ∠4

8 0
3 years ago
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