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2 years ago

Simplify (x – 3) (232 – 4x – 7)

Mathematics

2 answers:

jasenka [17]2 years ago

4 0

Answer:

-4x^2+232x-675

Step-by-step explanation:

x*(232-4x-7)-3(232-4x-7) remove the term from the first parentheses and multiple. Then, remove the parentheses .

232x-4x^2-7x-696+12x+21 Calculate the like terms and then rearrange.

=-4x^2+232x-675.

Hope that helps.

11111nata11111 [884]2 years ago

3 0

Answer:

-4x^2 + 237x - 675

Step-by-step explanation:

(x - 3)*(232 - 4x -7) >> Distribute x and -3 to the trinomial

232x - 4x^2 - 7x - 696 + 12x + 21 >> Simplify

-4x^2 + 237x - 675

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valentinak56 [21]

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2 years ago

If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers

seraphim [82]

Answer:

a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

$\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}$

<h2>Simplify it in steps:</h2>

Bring both fractions into common denominator:

$\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}$

Simplify:

$\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =$

$\dfrac{4\sqrt{14} }{7-4} =$

$\dfrac{4}{3} \sqrt{14} }$

Compare the result with given expression to get:

a = 4/3 and b = 0

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2 years ago

15% of R560 - 15% of R500 is:

Dahasolnce [82]

15% of R560 - 15% of R500

=> 0.15 × 560 – 0.15 × 500

=> 0.15 ( 560–500)

=> 0.15 × 60

=> Rs. 9

HOPE IT HELPS

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2 years ago

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STatiana [176]

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3 years ago

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Finger [1]

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2 years ago