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Juliette [100K]
3 years ago
14

How many years from 1848-2015

Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0
167 years.  You can get this by subtracting 2015 by 1848.
Luba_88 [7]3 years ago
6 0
I think it will be 167 years
2015-1848=167
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Jana ran the first 3 and a half miles of a 5 mile race in 1 3rd of an hour. what was her average rate, in mph, for the first par
Lisa [10]

Answer:

always try to draw a diagram first

Step-by-step explanation:

Jana ran The first 3.5 miles in 1/3 of an hour. remember the problem tells us that we want our answer in miles per hour or mph. so we have to set up our problem so that our units match in the end. The diagram above shows 3.5 mi over 1/3 hour. so we must divide 3.5 miles by 1/3 hour

note:

3 \frac{1}{2} mi =  \frac{7mi}{2}

therefore

\frac{7mi}{2}  \:  \div  \:  \frac{1hr}{3}  =

\frac{7mi}{2}  \times  \frac{3}{1hr}  =  \frac{21mi}{2hr}  = 10 \frac{1}{2}  \frac{mi}{hr}

7 0
2 years ago
PLLLLLLSSSSSS Help Will Mark Brainlest but must explain what you did in 20 minutes
padilas [110]

Answer:

A) The price of product A is increasing by 3% per year.

(B) The product A recorded a greater percentage change in price over the previous year.

Step-by-step explanation:

(A)

The function representing the price, in dollars, of product A after x years is:

FA(x)=0.69*(1.03)x

The function  FA(x)can be written as:

FA(x)=0.69*1+(0.03)x

The function FA(x) is similar to the exponential growth function, y=a(1+r)x .

Here r is the growth rate.

Thus, it can be said that the price of product A is increasing by 3% per year.

(B)

Consider the data of product B for the year 3 and 4.

The price of product B for year 3 and 4 are 10,303.01 and 10,406.04.

Compute the percent price change from year 3 to 4 as follows:

10406.04-10303.01/10303.01*100

which is 0.999%

~1%

The price of product B is increasing by 1% per year.

Thus, the product A recorded a greater percentage change in price over the previous year.

4 0
3 years ago
Identify the domain and range of the function f(x) = 2x2 − 6x − 9.
mash [69]
Range is the y values or ouputs
domain is inputs or x vvalues

we can use any x value
but at a certain y value, w can't go below that
find thatminimum
find the vertex
for
ax^2+bx+c
the x value of the vertex is
-b/2a
plug that in to the equaiton to get the y value

-b/2a=-(-6)/(2*2)=6/4=3/2

plug that in
2(3/2)^2-6(3/2)-9
2(9/4)-9-9
9/2-18
4.5-18
-13.5

domain=all real numbers
range=from -13.5 to positive infinity
4 0
3 years ago
Find the area of this figure
miv72 [106K]
52 is the answer to this question
8 0
2 years ago
Read 2 more answers
36/45 reduced in the lowest terms
malfutka [58]

Answer:

\frac{4}{5}

Step-by-step explanation:

They both (36 and 45) go into 9. Divide them both by 9.

\frac{4}5}

6 0
3 years ago
Read 2 more answers
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