<span>Volume; Liquid its the answer to your question</span>
There are nine possible combinations as follows: bb, bc, bt, cb, cc, ct, tb, tc, tt, each having a probability of 1/9. The four combinations with a cab exactly one time are: bc, cb, ct, tc. Therefore the probability that she'll use a cab exactly one time is: 4/9.
Answer:
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$36 because 20% of 45 is 9 and 45 - 9 is 36!
Answer:
No Solutions.
Step-by-step explanation:
I will solve your system by substitution.
3y−3=3x; −3x+3y=−57
Step: Solve 3y−3=3x for y:
3y−3+3=3x+3 (Add 3 to both sides)
3y=3x+3
(3y/3=3x+3)/3
(Divide both sides by 3)
y=x+1
Step: Substitute x+1 for y in −3x+3y=−57:
−3x+3y=−57
−3x+3(x+1)=−57
3=−57 (Simplify both sides of the equation)
3+(−3)=−57+(−3) (Add -3 to both sides)
0=−60
