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3 years ago

PLEASSSE HELP ASAP PRETTY PLEASEEEEEEE

Mathematics

2 answers:

CaHeK987 [17]3 years ago

6 0

Answer:

Third option. I am sure it!

Step-by-step explanation:

Mark other guy brainliest. He's a great answer and he helped me before

nadezda [96]3 years ago

3 0

Answer:

The third option choice

Step-by-step explanation:

Here you have the term (n^-6)(p^3)

(n^-6)(p^3) = (n^-6)(p^3)/1

[And whole number can be written over 1. For example, 4 = 4/1.]

You can see that n has a negative exponent, -6.

My teacher taught it to me like this:

If this is our expression;

(n^-6)(p^3)

--------------- <------ [and thats a fraction bar]

Think of the fraction bar as a bunk bed. Since the (n^-6) isn't happy being "on top of the bunk bed," [since its a negative exponent] move it to the bottom bunk.

So your new expression would be:

(p^3)

-------------- <-------- [fraction bar]

(n^6)

Moving n^6 to the bottom changes it into a positive exponent.

So, the third option choice would be correct.

That's the best way I can explain it! I hope this helps!!! :)

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When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100

ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the future value FV.

In order to see the rule of formation, let's see the value (in $) for the first few years

End of year 0

1,000

End of year 1(capital + interest + new deposit)

1,000*(1.09)+10

End of year 2 (capital + interest + new deposit)

(1,000*(1.09)+10)*1.09 +10 =

$\bf 1,000*(1.09)^2+10(1+1.09)$

End of year 3 (capital + interest + new deposit)

$\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)$

and we can see that at the end of year 50, the future value is

$\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}$

The sum

$\bf 1+1.09+(1.09)^2+...+(1.09)^{49}$

is the sum of a geometric sequence with common ratio 1.09 and is equal to

$\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356$

and the future value is then

$\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564$

The present value PV is

$\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62$

rounded to the nearest hundredth.

5 0

3 years ago

Find the product and 220 and 4

Alecsey [184]

220 x 4 = 880. //////

6 0

3 years ago

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Complete the proof proving YUZ~VWZ

iVinArrow [24]

Answer:

1. ΔXYZ is a right Δ with altitude YU.

Given

2. ΔXYZ ~ ΔYUZ

Right Triangle Altitude Similarity Theorem

3. VW || XY

Given

4. ∠VWZ ≅ ∠XYZ

Corresponding angles

5. ∠Z ≅ ∠Z

Reflexive property of congruence

6. ΔXYZ ~ ΔVWZ

AA Similarity postulate

7. ΔYUZ ~ ΔVWZ

Transitive property of similar triangles

Step-by-step explanation:

The first statement is given in the problem. Since we know the altitude of a right triangle, we can use the Right Triangle Altitude Similarity Theorem to say that the triangles formed by the altitude are similar to each other and the original triangle.

Next, we are given in the problem statement that the lines VW and XY are parallel. Therefore, ∠VWZ and ∠XYZ are corresponding angles, which makes them congruent. And since ∠Z is equal to itself (by reflexive property), we can use AA similarity to say ΔXYZ and ΔVWZ are similar.

Finally, combining statements 2 and 6, we can use transitive property to say that ΔYUZ and ΔVWZ are similar.

4 0

3 years ago

Y=2x-15 y=5x what the x equals

daser333 [38]

Answer:

16y=13x

Step-by-step explanation:

this honestly doesn't make sense but this is as much as i could simplify

7 0

3 years ago

Which statements are true about the interquartile range? Select all that apply.

PilotLPTM [1.2K]

Answer:

The true statements are:

B. Interquartile ranges are not significantly impacted by outliers

C. Lower and upper quartiles are needed to find the interquartile range

E. The data values should be listed in order before trying to find the interquartile range

Step-by-step explanation:

The interquartile range is the difference between the first and third quartiles

Steps to find the interquartile range:

Put the numbers in order
Find the median Place parentheses around the numbers before and after the median
Find Q1 and Q3 which are the medians of the data before and after the median of all data
Subtract Q1 from Q3 to find the interquartile range

The interquartile range is not sensitive to outliers

Now let us find the true statements

A. Subtract the lowest and highest values to find the interquartile range ⇒ NOT true (because the interquartial range is the difference between the lower and upper quartiles)

B. Interquartile ranges are not significantly impacted by outliers ⇒ True (because it does not depends on the smallest and largest data)

C. Lower and upper quartiles are needed to find the interquartile range ⇒ True (because IQR = Q3 - Q2)

D. A small interquartile range means the data is spread far away from the median ⇒ NOT true (because a small interquartile means data is not spread far away from the median)

E. The data values should be listed in order before trying to find the interquartile range ⇒ True (because we can find the interquartial range by finding the values of the upper and lower quartiles)

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3 years ago

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