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Sergio039 [100]
3 years ago
12

PLEASSSE HELP ASAP PRETTY PLEASEEEEEEE

Mathematics
2 answers:
CaHeK987 [17]3 years ago
6 0

Answer:

Third option. I am sure it!

Step-by-step explanation:

Mark other guy brainliest. He's a great answer and he helped me before

nadezda [96]3 years ago
3 0

Answer:

The third option choice

Step-by-step explanation:

Here you have the term (n^-6)(p^3)

(n^-6)(p^3) = (n^-6)(p^3)/1

[And whole number can be written over 1. For example, 4 = 4/1.]

You can see that <em>n</em> has a negative exponent, -6.

My teacher taught it to me like this:

If this is our expression;

(n^-6)(p^3)

---------------  <------ [and thats a fraction bar]

       1

Think of the fraction bar as a bunk bed. Since the (n^-6) isn't happy being "on top of the bunk bed," [since its a negative exponent] move it to the bottom bunk.

So your new expression would be:

 (p^3)

--------------  <-------- [fraction bar]

 (n^6)

Moving n^6 to the bottom changes it into a positive exponent.

So, the third option choice would be correct.

That's the best way I can explain it! I hope this helps!!! :)

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Basing the results on Probability is calculation. The correct option among all the options that are given in the question is the third option or option "c". Probability is basically calculating the chance of an event happening based on an experiment that is performed. I hope the answer comes to your help.
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24-4x=2x<br> show your work, will mark brainliest
vladimir2022 [97]

Answer:

x=4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

24−4x=2x

24+−4x=2x

−4x+24=2x

Step 2: Subtract 2x from both sides.

−4x+24−2x=2x−2x

−6x+24=0

Step 3: Subtract 24 from both sides.

−6x+24−24=0−24

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PLEASE HELP
Tems11 [23]

QUESTION A

The given multiplication problem is

\frac{39}{64} \times \frac{8}{13}

Factor each term to obtain;

\frac{13\times 3}{8\times8} \times \frac{8}{13}

Cancel out the common factors to obtain;

\frac{1\times 3}{8\times1} \times \frac{1}{1}

Simplify to get;

\frac{3}{8}

QUESTION B

The given multiplication problem is

\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}

This the same as

\frac{2\times 1\times 4}{3\times 5\times 7}

This simplifies to;

\frac{8}{105}

QUESTION C

The given problem is

\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}

This is the same as

\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}

=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}

This simplifies to

=\frac{1}{4}

QUESTION D.

The given expression is

\frac{4}{9}\times 54

Factor the 54 to obtain;

\frac{4}{9}\times 9\times 6

Cancel the common factors to get;

\frac{4}{1}\times 1\times 6

This simplifies to;

=24

QUESTION E

The given problem is

20\times 3\frac{1}{5}

Convert the mixed numbers to improper fraction to obtain;

=20\times \frac{16}{5}

=4\times5 \times \frac{16}{5}

Cancel the common factors to get;

=4\times1 \times \frac{16}{1}

=64

QUESTION F

The multiplication problem is

11 \times 2 \frac{7}{11}

Convert the mixed numbers to improper fractions to obtain;

11 \times \frac{29}{11}

Cancel out the common factors to get;

=1 \times \frac{29}{1}

Simplify;

=29

QUESTION G

The given problem is

5\frac{1}{3}\times 5\frac{1}{8}

Convert to improper fractions;

=\frac{16}{3}\times \frac{41}{8}

Cancel out the common factors to get;

=\frac{2}{3}\times \frac{41}{1}

=\frac{82}{3}

Convert back to mixed numbers

=27\frac{1}{3}

QUESTION H

The given expression is

10\frac{2}{3} \times 1\frac{3}{8}

Convert to improper fraction to get;

\frac{32}{3} \times \frac{11}{8}

Cancel common factors to get;

=\frac{4}{3} \times \frac{11}{1}

Simplify

=\frac{44}{3}

Convert back to mixed numbers;

=14\frac{2}{3}

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