Question

Carl drew a rectangle with a width of 8 in. And a length of 32 in. Which rectangles are not similar to Carl’s rectangle? Select ALL that apply.

Answer 1

Answer:

1) A rectangle with width of 10 cm and length of 44 cm.

4) A rectangle with width of 9 mm and length of 45 cm.

Step-by-step explanation:

Given:

Length of the rectangle = 32 in.

Width of the rectangle = 8 in.

Now we will find the ratio of length by width.

$\frac{length}{width}= \frac{32}{8} = \frac{4}{1} \ \ \ \ equation \ 1$

Now we need to find from the given Option which rectangles are not similar to Carl's Rectangle.

So we will check for each.

1) A rectangle with width of 10 cm and length of 44 cm.

Now we will find the ratio of length by width.

$\frac{length}{width}= \frac{44}{10} = \frac{11}{5} \ \ \ \ equation \ 2$

Now we know that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $\neq$ equation 2

Hence This rectangle is not similar to Carl's rectangle.

2) A rectangle with width of 2.5 inch and length of 10 inch.

Now we will find the ratio of length by width.

$\frac{length}{width}= \frac{10}{2.5} = \frac{4}{1} \ \ \ \ equation \ 2$

Now we know that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $=$ equation 2

Hence This rectangle is similar to Carl's rectangle.

3) A rectangle with width of 23 cm and length of 92 cm.

Now we will find the ratio of length by width.

$\frac{length}{width}= \frac{92}{23} = \frac{4}{1} \ \ \ \ equation \ 2$

Now we know that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $=$ equation 2

Hence This rectangle is similar to Carl's rectangle.

4) A rectangle with width of 9 mm and length of 45 cm.

Now we will find the ratio of length by width.

$\frac{length}{width}= \frac{45}{9} = \frac{5}{1} \ \ \ \ equation \ 2$

Now we know that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $\neq$ equation 2

Hence This rectangle is not similar to Carl's rectangle.