2cos²x+cos x-1=0
cos x=t
2t²+t-1=0
t=[-1⁺₋√(-1+8)]/2=(-1⁺₋3)/4
We have two possible set solutions:
First set solutions.
t₁=(-1-3)/2=-4/4=-1
cos x=-1 ⇒x=cos⁻¹ (-1)=π +2kπ or 180º+360ºk (k=(...-2,-1,0,1,2...)
Second set solutions:
t₂=(-1+3)/4=2/4=1/2
cos x=1/2 ⇒ x=cos⁻¹ 1/2=π/3+2kπ U 5π/3+ 2kπ or
60º+360ºK U 300º+360ºK (k=...-2,-1,0,1,2,...)
solutions: first set solutions U second set solutions:
Answer in radians : π +2kπ U π/3+2kπ U 5π/3+ 2kπ (k=...-1,0,1,...)
Answer is degrees: 180º+360ºk U 60º+360ºK U 300º+360ºK (k=...-2,-1,0,1,2,...)
Answer:
The answer would be -5/12
Step-by-step explanation:
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Answer: The first one is 9/49 and in decimal form it's 0.18367... the second one in fraction form is 16807/161051 and in decimal form is 0.10435824...
Step-by-step explanation: hope this helped
Answer:
x = -2,1,3
Step-by-step explanation:
Given: The curved line represented by the function crosses the x-axis at and y-axis at
To find: value of x for which
Solution:
= gives those values of x for which the curve represented by the given function cuts the x-axis.
According to question, the curve cuts the x-axis at
