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myrzilka [38]
2 years ago
8

Un bloc de la ville de New York a été représenté dans une grille. Chaque case contient un immeuble de

Mathematics
1 answer:
Andreas93 [3]2 years ago
4 0

Step-by-step explanation:

nznnzznsnsnsnnsnznxnxzmsksk

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Need help for this question
Bond [772]

Answer:

Step-by-step explanation:

608 square inches

5 0
3 years ago
Please I need help !!!!!
Mama L [17]
The formula is y=0.5m+20

You start (0,20) then for each mile you increase by 0.5.
Or
Since the x axis is by two, then every two miles you increase by 1 mile. So (0,20); (2,21); (4,22); (6,23); (8,24).

4 0
3 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
The assignment is about : Subtract Polynomials What i have to do : Subtract the polynomials, showing all the steps necessary to
lawyer [7]
1. 3x^1 + 8 - (2x^2 + 1).....distribute the negative thru the parenthesis
    3x^1 + 8 - 2x^2 - 1....now combine like terms
    -2x^2 + 3x^1 + 7

2. 5x^2 + 3x - 4 - (x^2 - 6x)...same thing..distribute
    5x^2 + 3x - 4 - x^2 + 6x...combine like terms
    4x^2 + 9x - 4
6 0
3 years ago
the boiling of jet fuel is 390f. rounded t the nearest degree, what is the temperature in degrees celsius? where c represents de
e-lub [12.9K]
390f = 198.889c
Hope this helps! 
7 0
3 years ago
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