Answer:
I got 3
Step-by-step explanation:
If you do 8 x 1/2 x 3 You would get 12. Keep that 12 for later. then for the bottom half do 2 x 1/2 x 4 and I got 4. so do 12/4 and then that goes to 3.
Total number of ways to make a pair:
The first player can be any one of 7 . For each of those . . .
The opponent can be any one of the remaining 6 .
Total ways to make a pair = 7 x 6 = 42 ways .
BUT ... every pair can be made in two ways ... A vs B or B vs A .
So 42 'ways' make only (42/2) = 21 different pairs.
If every pair plays 2 matches, then (21 x 2) = <em><u>42 total matches</u></em> will be played.
Now, is that an elegant solution or what !
The zeros of the function occur when the graph meet the x-axis so in this case the zeros occur at B ( 0 and 5)
Answer:
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Step-by-step explanation:
The cost of a senior citizen ticket is $15 and the cost of a student ticket is $12.
How did I get this?
We know that 6 citizen tickets and 7 student stickers sold for $174 the first day. And 10 citizen tickets and 14 student tickets sold for $318 the second day.
1. create two equations out of this: C= citizen cost per ticket and S = student cost per ticket.
6C + 7S = $174
10C + 14S = $318
2. Use process of elimination. Multiply the first equation by 2 because we want two variables to cancel out.
-12C - 14S = -$348
10C + 14S = $318
Combine like terms.
-2C = $30
Divide by -2 on both sides. The left side cancels out.
C = $30/-2
C = -$15 (In this case the negative doesn't matter)
C = $15 (cost of senior citizen ticket)
Plug the value of C into any of the two equations so we can get the value of S.
6($15) + 7S = $174
Distribute the 6 into the parenthesis.
$90 + 7S = $174
Subtract both sides by $90 and the left side will cancel out.
7S = $84
Divide both sides by 7.
S = $12
Student ticket: $12
Senior citizen ticket: $15