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Crank
2 years ago
15

11. FOUR 4's. Using only four 4's, the operations (+,-, x, +), and parentheses,

Mathematics
1 answer:
Marysya12 [62]2 years ago
7 0

Answer:

  see below

Step-by-step explanation:

You want an arithmetic expression using four 4s that evaluates to each of the digits 0-9.

<h3>Expressions</h3>

0 = 4 +4 -4 -4

1 = 4/4 +4 -4

2 = 4 -(4 +4)/4

3 = (4 +4 +4)/4

4 = 4 + (4 -4)*4

5 = (4*4 +4)/4

6 = 4 +(4 +4)/4

7 = 4 +4 -4/4

8 = 4 +4 +4 -4

9 = 4 +4 +4/4

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You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confide
FrozenT [24]

Question:

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$114.00. Assume the population standard deviation is ​$15.30. Construct a​ 90% confidence interval for the population mean.

Answer:

At the 90% confidence level, confidence interval = 110.2484 < μ < 117.7516

At the 95% confidence level, confidence interval = 109.53 < μ < 118.48

The 95% confidence interval is wider

Step-by-step explanation:

Here, we have

Sample size, n = 45

Sample mean, \bar x = $114.00

Population standard deviation, σ = $15.30

The formula for Confidence Interval, CI is given by the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Where, z is found for the 90% confidence level as ±1.645

Plugging in the values, we have;

CI=114\pm 1.645 \times \frac{15.3}{\sqrt{45}}

or CI: 110.2484 < μ < 117.7516

At 95% confidence level, we have our z value given as z = ±1.96

From which we have CI=114\pm 1.96 \times \frac{15.3}{\sqrt{45}}

Hence CI: 109.53 < μ < 118.48

To find the wider interval, we subtract their minimum from the maximum as follows;

90% Confidence level: 117.7516 - 110.2484 = 7.5

95% Confidence level: 118.47503 - 109.5297 = 8.94

Therefore, the 95% confidence interval is wider.

8 0
3 years ago
Read 2 more answers
Can someone help?
nalin [4]
No no no no no no no no no jk its c your welcome
7 0
3 years ago
James works in a sporting goods store and earns $324 a week and 5% of his sales. One week James earned $432. What were his sales
Bogdan [553]

Answer:

His sales that week were $2,160.

Step-by-step explanation:

First, you have to subtract $324 from the amount he earned that week, to find the 5% he got from sales:

$432-$324=$108

Now, you know that he received $108 that represent 5% of his sales and you can use a rule of three to find the amount that represents 100% which would be his sales that week:

 5%   →    108

100% →      x

x=(100*108)/5=2160

According to this, the answer is that his sales that week were $2,160.

7 0
3 years ago
What is the product in simplest form x^2+9x+18/x+2 times x^2-3x-10/x^2+2x-24
german
\dfrac{x^2+9x+18}{x+2}\cdot\dfrac{x^2-3x-10}{x^2+2x-24}=\dfrac{x^2+6x+3x+18}{x+2}\cdot\dfrac{x^2-5x+2x-10}{x^2+6x-4x-24}\\\\=\dfrac{x(x+6)+3(x+6)}{x+2}\cdot\dfrac{x(x-5)+2(x-5)}{x(x+6)-4(x+6)}

=\dfrac{(x+6)(x+3)}{x+2}\cdot\dfrac{(x-5)(x+2)}{(x+6)(x-4)}=\dfrac{(x+3)(x-5)}{x-4}\\\\=\dfrac{x^2-5x+3x-15}{x-4}=\dfrac{x^2-2x-15}{x-4}
5 0
3 years ago
Read 2 more answers
Is 0.35 grater than 300 mL
Sveta_85 [38]

Answer:

yes

Step-by-step explanation:

yes

6 0
2 years ago
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