Question 11 of 12

Mathematics

2 answers:

iogann1982 [59]3 years ago

6 0

Answer:

By ASA

Step-by-step explanation:

<SVR=<VRT (ALTERNATE ANGLES)

SIDE RV=SIDE RV (COMMON)

<SRV=<TVR (ALTERNATE ANGLES)

So by side angle side postulate both triangles are congruent

Hope u understand

Brainliest?

chubhunter [2.5K]3 years ago

5 0

Step-by-step explanation:

Sorry I'm not too sure about that one, but this video might help, sorry!

https://youtu.be/JtgABYPsv7g

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WIll GIVE BRAINLYEST TO WHOEVER ANSWERS BOTH QUESTIONS FIRST CORRECTLY

omeli [17]

Answer:

1. 8.4 in 2. 33.6

Step-by-step explanation:

6 0

3 years ago

A. DG<br>B. AD<br>C. DC<br>D. AB

solmaris [256]

It’s DG.

A parallel segment to CF is one that will never cross CF and goes in the same direction.

AD is booted because it is going horizontally and not up like CF.

DC is booted also because it is going horizontally and it will cross CF.

AD isn’t the correct answer because it is going horizontally and not in the same direction as CF.

8 0

3 years ago

The base of a solid is the region in the first quadrant bounded by the line x=-2y+6 and the coordinate axes. What is the volume

nika2105 [10]

Answer:

$V = \frac{4y^3}{3} -12y^2 +36 y \Big|_0^3$

$V= \frac{4(3)^3}{3} -12(3)^2 +36 (3) -0 = 36-108+108= 36$

Step-by-step explanation:

For this case we have the following plot on the figure attached.

We know on this case that $x = -2y+6$ represent our radius for the square, since we need cross sections perpendicular to the y axis.

We find the intersection points like this:

$x= 0 , y=3$

$y=0, x=6$

Since we are assuming squares for the cross sections the area is given by $A = r^2$ where r = x= -2y+6.

Since our radius is on terms of x we can create a integral with limits on x in order to find the volume, And we can use the following integral in order to find the volume.

$V = \int_{0}^3 (-2y+6)^2 = \int_{0}^3 4y^2 -24y +36 dy$