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3 years ago

I NEED HELP (look below)

Mathematics

2 answers:

tino4ka555 [31]3 years ago

7 0

Answer:

e=mc²

Step-by-step explanation:

as e=mc² so e=mc square of mc donalds

telo118 [61]3 years ago

3 0

Answer:

Step-by-step explanation:

Points earned for 'w' words + points earned for each 6-letter word - the points taken away for 't' tiles that are not used

= 10w + 5 - 3t

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Help please due soon

ANEK [815]

Answer: c=24

Step-by-step explanation: 15×3=45. 8×3=24. Just multiply both the numerator and denominator by 3.

5 0

3 years ago

Read 2 more answers

Each of the sides of a pentagon is 12 cm long. Two ants are walking from point A to point D along the sides of the pentagon. One

AVprozaik [17]

Answer:

The average speed of the second ant is 2 cm/s

Step-by-step explanation:

The details of the ants moving on the sides of the pentagon are;

The length of the sides of the pentagon = 12 cm

The path of the first ant = A to B, B to C, then C to D

The average speed of the first ant = 3 cm/s

The path of the second ant = A to E, and E to D

The time of arrival of the second ant at the point D = The time of arrival of the first ant at the point D

Given that both ants departed at the same time, from point A, we have;

The time it takes the first ant to arrive at the point D = The time it took the second ant to arrive at the point D

The distance from A to B = 12 cm

The distance from B to C = 12 cm

The distance from C to D = 12 cm

∴ The distance traveled by the first ant from A to D = 12 cm + 12 cm 12 cm = 36 cm

Average speed = (Total distance)/(Total Time)

Total time = (Total distance)/(Average speed)

Let 't' represent the time it takes the first ant to move from point A to point D, we have;

t = 36 cm/(3 cm/s) = 12 seconds

Therefore, the time it takes the first ant to move from point A to point D, t = 12 seconds = The time it takes the second ant to move from point A to point D through point E

The total distance traveled by the second ant from A to point E, then from point E to point D, $T_{d2}$ = 12 cm + 12 cm = 24 cm

The average speed of the second ant, v₂ = $T_{d2}$ /t

∴ v₂ = 24 cm/(12 seconds) = 2 cm/s

The average speed of the second ant, v₂ = 2 cm/s.

8 0

3 years ago

A train stops at Atlanta, then at Bayville, and then at Colleyville. The

Nezavi [6.7K]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as what is required of the question is not stated.

However, since the question is only limited to distance, a likely question could be to calculate the distance from Bayville to Colleyville.

Represent the distance from Atlanta to Colleyville with AC

Represent the distance from Atlanta to Bayville with AB

Represent the distance from Bayville to Colleyville with BC

So, we have that:

$AC = 25.5\ miles$

$AB = 10\frac{2}{3}\ miles$

The relationship between AB, AC and BC is:

$AC = AB + BC$

Make BC the subject of formula:

$BC = AC - AB$

$BC = 25.5 - 10\frac{2}{3}$

Convert fraction to decimal

$BC = 25.5 - 10.7$

$BC = 14.8$

Hence, the distance from Bayville to Colleyville is 14.8 miles

3 0

3 years ago

Chen rode his skateboard 3 3 4 miles in 3 4 of an hour. What was his average speed in miles per hour?

Sati [7]

The answer is 5 .

3 3/4 / 3/4 = 5
Hope this helps

7 0

3 years ago

The equation of a function y = 2/3x+1/3 find the value of y when x = -3 when x = 1 1/2

kirill [66]

Answer:

$y = \frac{-5}{3}\\\\y = \frac {4}{3}$

Step-by-step explanation:

$y = \frac{2}{3} x + \frac{1}{3}\\\\when \ x = -3 \\\\y = \frac{2}{3}(-3) + \frac{1}{3} = -2 + \frac{1}{3} = \frac{-6 + 1}{3}= \frac{-5}{3} \\\\When \ x = 1 \frac{1}{2} = \frac{3}{2}\\\\y = \frac{2}{3} \times \frac{3}{2} + \frac{1}{3} = 1+ \frac{1}{3} = \frac{3 + 1}{3}= \frac{4}{3} \\\\$

5 0

3 years ago