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AysviL [449]
3 years ago
9

In a certain card game you draw one card off a standard deck of 52 cards. If you draw a spade you get paid $12, if you draw a re

d Ace you get paid $20, and if you draw a red Queen you get paid $38. If you draw anything else, you get paid nothing. What should this game cost if it is to be a fair game? Use fractions in your work and then calculate the answer as a decimal rounded to 4 decimal places.
Mathematics
1 answer:
Mariulka [41]3 years ago
4 0

Step-by-step explanation:

In a standard deck of 52 cards, there are 2 red aces, 2 red Queens, and 13 spades.  That leaves 35 cards for everything else.

For the game to be fair, the cost must equal the expected value.  The expected value is the sum of each outcome times its probability.

C = (12) (13/52) + (20) (2/52) + (38) (2/52) + (0) (35/52)

C = 68/13

C ≈ 5.2308

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Hey there!

One way to do this is find all the factors of 6 and then see which pair fit the requirements.

The factors of 6 are 1, 2, 3, and 6. (Note: There can be negative factors, but I am going to leave them out since it is asking for positive integers.)

You can find them by asking if each number can go into 6.

1, 2, 3, and 6 all go into 6, while 4 and 5 do not.

The requirements we have is that they must be consecutive <u>and</u> have a product of 6.

Consecutive means right after one another.

The only numbers that fit this are 2 and 3.

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Hope this helps!

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