Solve m∠1 through m∠7

Someone, please help me with this question.

Viefleur [7K]

Answer:

C. 95°

Step-by-step explanation:

Sumplementary angles sum 180°

144° + a = 180°

a = 180° - 144°

a = 36°

121° + b = 180°

b = 180° - 121°

b = 59°

The sum of internal angles of a triangle is 180°

a + b + c = 180°

36° + 59° + c° = 180°

c° = 180° - (36°+59°)

c° = 180° - 95°

c° = 85°

then:

c + n = 180°

85° + n = 180°

n = 180° - 85°

n = 95°

5 0

2 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

A piece of fabric is 1/3 yard by 3 5/8 yards. Irma solves 1/3⋅3 5/8 to find the area of the fabric in square yards. Enter number

Harlamova29_29 [7]

For this case we have:

The area of the piece of fabric is given by $A = a * b$

Where

$a = \frac{1}{3}yards$

$b = 3 \frac{5}{8}yards$

Substituting in the formula of the area we have:

$A = \frac{1}{3}* 3 \frac{5}{8}\\$

$A = \frac{1}{3}* (3 + \frac{5}{8})\\$

$A = 1 + \frac{5}{24}$

$A = 1\frac{5}{24}yards ^ 2\\$

Thus, the area of the piece of fabric is given by: $A = 1\frac{5}{24}yards ^ 2\\$

Answer:

$A = 1\frac{5}{24}yards ^ 2\\$

4 0

3 years ago

Please answer asap!!<br>

fredd [130]

Answer:

A

Step-by-step explanation:

6 is about halfway to 16

21 is about halfway to 56

they meet up, which makes the line the most accurate

Yw :D

7 0

2 years ago

Why is a parallelogram not the same type of quadrilateral as trapezoid

Alisiya [41]

A quadrilateral trapezoid means that there are four sides to the trapezoid. But two of those sides (which are across from each other if you were to draw it out) are not parallel, meaning that if you were to continue the lines they start from, they would eventually cross. A parallelogram means that all opposite sides are parallel. Hope this helps you!! :)

7 0

2 years ago