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Kisachek [45]
3 years ago
14

1.7 In the following diagram, angle 7 equals 61°.

Mathematics
2 answers:
gladu [14]3 years ago
7 0
1.7) < 7 and < 8 form a linear pair....which means, when added, they equal 180 degrees. So if < 7 = 61, then < 8 = (180 - 61) = 119 <=

1.8) angles that are supplementary will add up to 180. So if one of the angles is 38, then the other one is (180 - 38) = 142 <==

1.9) < 3 = < 5 (vertical angles are congruent)
1.10) < 2 = < 8 (vertical angles are congruent)
1.11) < 7 = < 1 (vertical angles)
1.12) < 6 = < 4 (vertical angles)
Zepler [3.9K]3 years ago
4 0
1.7 ) 180-61 = 119
1.8 ) 180 -38 = 142
1.9 ) 5
1.10) 8
1.11) 1
1.12 ) 4
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Tangent is positive in quadrants I and IV only.<br>True or False
zhannawk [14.2K]

Answer:

The statement is false

Step-by-step explanation:

we know that

tan(x)=\frac{sin(x)}{cos(x)}

The tangent function will be positive when the sine function and the cosine function have the same sign

so

In the first quadrant the tangent function is positive

In the third quadrant the tangent function is positive

so

The statement is false

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3 years ago
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The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.
andrezito [222]

Answer:

Given the equation: 3x^2+10x+c =0

A quadratic equation is in the form: ax^2+bx+c = 0 where a, b ,c are the coefficient and a≠0 then the solution is given by :

x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a} ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}

Simplify:

x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}

Also, it is given that the difference of two roots of the given equation is 4\frac{2}{3} = \frac{14}{3}

i.e,

x_1 -x_2 = \frac{14}{3}

Here,

x_1 = \frac{-10 + \sqrt{100- 12c}}{6} ,     ......[2]

x_2= \frac{-10 - \sqrt{100- 12c}}{6}       .....[3]

then;

\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}

simplify:

\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}

or

\sqrt{100- 12c} = 14

Squaring both sides we get;

100-12c = 196

Subtract 100 from both sides, we get

100-12c -100= 196-100

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve x_1 , x_2

x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}

or

x_1 = \frac{-10 + \sqrt{100- 96}}{6} or

x_1 = \frac{-10 + \sqrt{4}}{6}

Simplify:

x_1 = \frac{-4}{3}

Now, to solve for x_2 ;

x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}

or

x_2 = \frac{-10 - \sqrt{100- 96}}{6} or

x_2 = \frac{-10 - \sqrt{4}}{6}

Simplify:

x_2 = -2

therefore, the solution for the given equation is: -\frac{4}{3} and -2.


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Jason considered two similar televisions at a local electronics store. The generic version was based on the brand name and was t
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Answer:

<em>The brand name television's dimensions are 32 inches by 64 inches.</em>

Step-by-step explanation:

<u>Scaling</u>

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If we knew the size of the brand name television, we would have to multiply its dimensions by 3/8, but instead, we have the dimensions of the generic television, so to find the brand name television, we multiply by 8/3.

12 inches * 8/3 = 32 inches

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Remove the bracket

y = -4(x + 2)² + 2


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