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3 years ago

PLEASE HELP!!

Mathematics

1 answer:

Sav [38]3 years ago

5 0

draw the triangle out and place all your given information in it to solve this.

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Match the scatter plot with its description

Crank

I would put in,
1.Moderate and positive
2.Moderate and negative
3.Weak and positive
4.Strong and negative

3 0

2 years ago

What are polynomials. And how many answers can there be for some?

NeTakaya

Answer:

an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).

its a Latin name with more than two parts.

and polynomials has 5 answers

3 0

3 years ago

Joe measured a brick using a ruler with centimeters and got 9 cm. He then measured the same brick using a ruler with millimeters

Natasha_Volkova [10]

Answer:

yes, the measures are equivalent because the formula for cm to mm is times 10. 9 times 10 is 90.

Step-by-step explanation:

hope this helps! pls mark brainliest!

8 0

3 years ago

Graph y= x−2. PLZZ HELP

nataly862011 [7]

Explanation: To graph the equation y = x - 2, the idea is simple.

We pick three values for x, plug them into the

equation, and find the corresponding values for y.

In order to do this in an organized way, we set up a chart.

Down the left side we make a column for our x's, down the right side we make a column for our y's, and in the middle we make a column for the side of the equation that contains the x, in this case, x - 2.

So reading the chart from left to right, we have our x or what we plug into the equation, then we have the x - 2 or what happens to the x when we plug it into the equation, and finally we have our y or what we end up with after plugging x into the equation.

So our first step in filling out the chart is choosing

the x's that we want to plug into the equation.

When graphing lines, I always choose three x's,

a positive number, zero, and a negative number.

The easiest numbers to pick are usually 1, 0, and -1.

So for 1, we plug a 1 into the equation for x

and we have y = (1) - 2 or -1

For 0 we plug a 0 into the equation for x

and we have y = (0) - 2 or -2.

For -1 we plug a -1 into the equation for x

and we have y = (-1) - 2 or -3.

So our points are (1, -1), (0, -2), and (-1, -3).

I looked at the x and y column to find those points.

Since our domain is all real numbers, we can connect these points based on the pattern that they are forming on the graph which is a line.

5 0

3 years ago

Read 2 more answers

Find all intervals on which the graph of f(x)=(x-1)/(x+3) is concave upward

Yuliya22 [10]

To find concavity we need to find the second derivative.
Use quotient rule to find f'(x)=4/(x+3)^2
Then use chain rule to find f''(x)=-8/(x+3)^3
To find potential inflection points, we need to find all x values where the second derivative is equal to 0 or is undefined.

Set the numerator and denominator equal to 0 and solve.

(x+3)^3=0
x+3=0
x= -3

Now plug a value less than -3 and greater than -3 into the second derivative to find where the concavity is upward (positive number).

Since f''(-4) is positive, that means that f(x) is concave up on the interval (-infinity, -3).

4 0

4 years ago