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2 years ago

Suppose two bicyclists start at the same location.

Mathematics

1 answer:

aliya0001 [1]2 years ago

7 0

Answer:

4 mi/h

Step-by-step explanation:

The distance between the cyclists is the hypotenuse of an isosceles right triangle. The hypotenuse is √2 times the length of the legs in such a triangle, so each cyclist must have ridden 8 miles in 2 hours.

Their speed is (8 mi)/(2 h) = 4 mi/h.

_____

<em>Additional comment</em>

Consider an isosceles right triangle with leg lengths 1. Then the Pythagorean theorem tells us the length of the hypotenuse is ...

c² = a² +b² . . . square of hypotenuse is sum of squares of legs

c² = 1² +1² . . . . both legs are 1 in our example triangle

c² = 2

c = √2

That is, the hypotenuse is √2 times the leg length.

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xxTIMURxx [149]

Greetings and Happy Holidays!

Solve for x.
$5x(x-6)(4x+9)=0$ <span>

Distribute the parenthesis:
</span> $5x(x-6)(4x+9)=0$

$(5x^2-30x)(4x+9)=0$

$(20x^3-120x^2)+(45x^2-270x)=0$

Combine like terms:
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Factor out GCF (5x):
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Factor the Complex Trinomial:
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or

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The Answers Are:
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I hope this helped!
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