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juin [17]
4 years ago
9

Can someone plz help me on this I really need help

Mathematics
1 answer:
Usimov [2.4K]4 years ago
5 0

When dividing fractions these are the steps you will take:

1. The first number in the expression stays the same. If it is a whole number then you may just place a one in the denominator and keep the numerator as the whole number like so:

\frac{3}{1} ÷ \frac{3}{4}

2. Change the division sign into a multiplication sign

\frac{3}{1} × \frac{3}{4}

3. Take the reciprocal (switch the places of numerator and denominator) of the second number in the expression

\frac{3}{1} × \frac{4}{3}

4. Multiply across

\frac{3*4}{1*3}

\frac{12}{3}

^^^This can be further simplified:

4

Hope this helped!

~Just a girl in love with Shawn Mendes

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7w -17=46 need help thanks
murzikaleks [220]

Answer:

w=9

Step-by-step explanation:

7w -17=46

Add 17 to each side

7w -17+17=46 +17

7w = 63

Divide each side by 7

7w/7 = 63/7

w=9

3 0
3 years ago
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The frequency of G5 is 783.99 Hz. What is the frequency of the note that is a perfect fifth above G5?
Dmitry [639]
<span>Give that </span>t<span>he frequency of G5 is 783.99 Hz.
To find the frequency of the note that is a perfect fifth above G5, we recall that </span>the frequencies of notes that are a 'perfect' fifth apart are in the ratio of 1.5

i.e. <span>the frequency of the note that is a perfect fifth above G5 divided by </span><span>t<span>he frequency of G5 equal 1.5

Let the </span></span><span><span>frequency of the note that is a perfect fifth above G5 be F, then
F / </span>783.99 = 1.5
F = 1.5 x 783.99 = 1175.99

Therefore, </span>the <span>frequency of the note that is a perfect fifth above G5</span> is 1175.99 Hz
3 0
4 years ago
Evaluate the expression 3 x<br> {10 +1} +5.
Tanya [424]

Answer:

38

Step-by-step explanation:

3 x {10 +1} +5.

PEMDAS

Parentheses first

3 x {11} +5.

Then multiply and divide

33+5

38

4 0
3 years ago
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2.
Annette [7]
The correct answer is b.
3 0
3 years ago
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Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 mo
Katarina [22]

Given:

Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 monthly service fee. Paco is trying to keep his bill for the month below $30.

To Find:

The number of texts 't' Paco can send/receive in a month.

Answer:

0\leq t

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

Step-by-step explanation:

Paco wants to keep is monthly bill below $30.

We see that he has to pay a foxed monthly service fee of $15. This means he is only left with a limit of $30 - $15 = $15 for his monthly calls and texts.

That is, the amount he has to pay for texting and calling has to be less than $15.

For texts, the cell phone carrier charges $0.20 for sending/receiving texts.

For calls, he is charged $0.15 per minute.

Let the number of text messages Paco can send or receive in a month be denoted by 't'.

Let the number of minutes Paco can call in a month be denoted by 'c'.

Then, the total cost of text messages he can send or receive per month would be 0.20t and the total cost of the minutes he spends on calls would be 0.15c. Together, the sum of these has to be less than $15 if his monthly bill has to be kept less than $30 (accounting for the monthly service fee).

So,

0.20t+0.15c

The number of texts he can send will dpend on the number of minutes he spends on his calls. For Paco to spend maximum number of texts, he has to spend 0 minutes on calls.

So, putting c = 0, the aboce equation can be written as

0.20t+0

That is, Paco has to send and receive less than 75 texts.

So,

0\leq t

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

3 0
3 years ago
Read 2 more answers
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