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Rus_ich [418]
3 years ago
14

The Gonzalez family sold their home for $256,000. Their real estate agent earned 5.5% in commission of that sale. How much did t

he Gonzalez family get to keep from the sale?
Mathematics
1 answer:
ra1l [238]3 years ago
6 0
The Gonzalez family kept 241,920 from the sale
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June is working on an addition problem and starts with 17,985. After she adds, she still has 17,985. Which property of addition
podryga [215]

Answer:

addition

Step-by-step explanation:

idkthis sounds dumb

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3 years ago
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Write an equivalent expression using distributive property and simplify for each question
Lana71 [14]

Answer:

Check explanations

Step-by-step explanation:

For all real numbers a,b, and c, the distributive property states that:

a(b + c) = ab + ac

For Part A, we have

2x + 10x = x(2 + 10) = x(12) = 12x

Or

2x + 10x = 2x(1 + 5) = 2x(6) = 12x

For Part B, we have

-4(3x-10)+5(2-6x)=-4*3x--4*10+5*2-5*6x

This simplifies to:

-4(3x-10)+5(2-6x)=-12x+40+10-30x

-4(3x-10)+5(2-6x)=-12x-30x+40+10

-4(3x-10)+5(2-6x)=-42x+50

For the C part, we have:

2(x - 4) + x = 2 \times x - 2 \times 4 + x

2(x - 4) + x = 2x - 8+ x

2(x - 4) + x = 3x - 8

For Part D, we have:

-3-7(3-4x)+8x =  - 3 - 7 \times 3  - 7 \times  - 4x + 8x

We simplify to get:

-3-7(3-4x)+8x =  - 24+28x + 8x

Simplify further to get:

-3-7(3-4x)+8x =-24+36x

4 0
3 years ago
Find the two square roots of the number 169
Mazyrski [523]

One root belonged to an old tree next to the road, and the other is part of a small tree.

4 0
3 years ago
Box of 15 gadgets is known to contain 5 defective gadgets if 4 gadgets are drawn at random what is the probability of finding no
baherus [9]

To solve this problem, we make use of the Binomial Probability equation which is mathematically expressed as:

P = [n! / r! (n – r)!] p^r * q^(n – r)

where,

n = the total number of gadgets = 4

r = number of samples = 1 and 2 (since not more than 2)

p = probability of success of getting a defective gadget

q = probability of failure = 1 – p

 

Calculating for p:

p = 5 / 15 = 0.33

So,

q = 1 – 0.33 = 0.67

 

Calculating for P when r = 1:

P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3

P (r = 1) = 0.3970

 

 

Calculating for P when r = 2:

P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2

P (r = 2) = 0.2933

 

Therefore the total probability of not getting more than 2 defective gadgets is:

P = 0.3970 + 0.2933

P = 0.6903

 

Hence there is a 0.6903 chance or 69.03% probability of not getting more than 2 defective gadgets.

5 0
3 years ago
Select the outlier in the data set.
Katarina [22]

Answer:

86

Step-by-step explanation:

21   <u>3</u>6

<em>5</em>2   <em>4</em>0

<u>3</u>2   <em><u>86</u></em>

<u>3</u>3   <u>3</u>8

28   <u>3</u>4

<u>3</u>0   <em>1</em>9

6 0
2 years ago
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