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Vedmedyk [2.9K]
4 years ago
4

Malachi is practicing math fluency. He has 100 math operation flashcards with 42 addition problem cards, 56 subtraction cards, a

nd 2 multiplication cards. He will time himself to see how fast he can solve the problems on two cards. He chooses his two cards and they are both multiplication cards. Is choosing two multiplication cards likely? Explain by running a simulation.
Mathematics
1 answer:
Sophie [7]4 years ago
3 0

Answer: No, chosing two multiplication cards is not likely.

Step-by-step explanation:

We have 100 cards in total.

42 of addition problems.

56 subtraction problems

2 multiplication problems.

The probability of drawing at random a multiplication card is equal to the number of cards dividedd by the total number of cards, this is:

p1 = 2/100

Now, in a second drawing the probability is calculated in the same way, but before we drawed one multiplication card, so we now have 99 cards in the pile and only one of the card is a multiplication problem.

The probability is p2 = 1/99.

Now, the joint probability of these two events is:

P = p1*p2 = (2/100)*(1/99) = 2/9900  = 1/4500 = 0.0002

The probability is really small, so this event is not likely.

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Jet had $63 to spend at Pet Smart. She spent 2/7 of her money on dog bones and the rest on squeaky toys to destroy. How much mon
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Answer:

She spent 45 dollars on squeaky toys.

Step-by-step explanation:

If we divide 63 by 7 we would get 9, then if we multiply that number by 2 for the bones, we are left with 5/7, finally if we multiply the 5 by 9 you would get 45, or 45 dollars.

3 0
3 years ago
Math help plss !! uwu im stuck.
Alexxx [7]

Step-by-step explanation:

1) The four points are:

(x₁, y₁) = (-2, -1)

(x₂, y₂) = (3, 13)

(x₃, y₃) = (15, 5)

(x₄, y₄) = (13, -11)

Using the distanced formula the four side lengths are:

d₁₂ = √((13−-1)² + (3−-2)²) = √221

d₂₃ = √((5−13)² + (15−3)²) = √208

d₃₄ = √((-11−5)² + (13−15)²) = √260

d₄₁ = √((-1−-11)² + (-2−13)²) = √325

None of the lengths are equal, so we know this isn't a rhombus, parallelogram, or kite.  Is it a trapezoid?  To find out, let's find the slopes between the two lines that look like they might be parallel.

m₂₃ = (5 - 13) / (15 - 3) = -2/3

m₄₁ = (-1−-11) / (-2−13) = -2/3

They are indeed parallel.  So this is a trapezoid.

2) Given:

PS ≅ QR

m∠P + m∠Q = 180

m∠R + m∠S = 180

∠P ≅ ∠S

By converse of Alternate Interior Angles Theorem, since ∠P and ∠Q are supplementary, line PS and QR must be parallel.

If a quadrilateral has one pair of opposite sides that are both parallel and congruent, then it is a parallelogram.

Adjacent angles of a parallelogram are supplementary, so m∠P + m∠S = 180.

Since ∠P ≅ ∠S, then by definition of congruent angles, m∠P = m∠S.

Substitution:

m∠P + m∠P = 180

m∠P = 90

Substitution:

m∠S = 90

Opposite angles of a parallelogram are congruent, so m∠Q = m∠S = 90 and m∠R = m∠P = 90.

A parallelogram with four right angles is a rectangle.

6 0
3 years ago
In the United States, the mean birth weight for boys is 3.41 kg with a standard deviation of 0.55 kg. Assume that the distributi
lyudmila [28]

Answer:

The proportion of baby boys in the United States that are born with low birth weight is 0.0495.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

3.41 kg with a standard deviation of 0.55 kg.

This means that \mu = 3.41, \sigma = 0.55

What proportion of baby boys in the United States are born with low birth weight?

This is the pvalue of Z when X = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.5 - 3.41}{0.55}

Z = -1.65

Z = -1.65 has a pvalue of 0.0495

The proportion of baby boys in the United States that are born with low birth weight is 0.0495.

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