I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
Answer:
-3x is the answer
Step-by-step explanation:
The answer is amortization
The y-intercept is (0,12), or just 12, hope this helps
<span>"Simplifying
0.2y = 0.5x + 0.1
Reorder the terms:
0.2y = 0.1 + 0.5x
Solving
0.2y = 0.1 + 0.5x
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Divide each side by '0.2'.
y = 0.5 + 2.5x
Simplifying
y = 0.5 + 2.5x"</span>
